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aniked [119]
1 year ago
12

A compound is composed of 22.5% phosphorus and 77.5% chlorine. the molecular mass of the compound is 137.32 g/mol. what is the m

olecular formula of the compound? pcl2 pcl3 p2cl3 pcl4
Chemistry
2 answers:
asambeis [7]1 year ago
7 0

The molecular formula of the compound is PCl₃ if the molecular mass of the compound is 137.32 g/mol.

An empirical formula can be described as a formula that tells about the relative ratios of different atoms in a compound.

The empirical formula for this compound containing phosphorus and chlorine can be calculated as follows;

As the compound is composed of 22.5% phosphorous and 77.5% chlorine, therefore;

Phosphorus = (22.5/100) × 137.32 = 0.225 × 137.32 = 30.897

Chlorine = (77.5/100) × 137.32 = 0.775 × 137.32 = 106.423

Now we can find the moles of each atom by using their molar mass as follows;

Phosphorus = 30.897 ÷ 30.97 = 0.998 moles

Chlorine = 106.423 ÷ 35.453 = 3.002 moles

Now dividing each mole value by the smallest determined number of moles (0.998) as follows;

Phosphorus = 0.998 / 0.998 = 1 mole

Chlorine = 3.002 / 0.998 = 3.008 ≈ 3 moles

Therefore the molecular formula of the compound will be PCl₃.

To learn more about the empirical formula; click here:

brainly.com/question/28080770

#SPJ4

Katena32 [7]1 year ago
4 0

Answer:

b

Explanation:

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