Answer:
again same questions
i think its from 1st chapter
D. the first shell can hold only a minimum of two electrons
0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.
The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.
The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.
Amount of NaOH = 36. 0 g
Amount of water = 1. 50 L
1 mol of NaOH = 40 g,
Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH
Molarity of a solution = moles of solute / Liters of solution
Molarity of a solution = 0.9 / 1.50
Molarity of a solution = 0.6 mol / L
To know more about Molarity refer to: brainly.com/question/8732513
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Full Question:
Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. Suppose 94g of sulfuric acid is mixed with 49.9g of sodium hydroxide. Calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.
Answer:
32.8725g
Explanation:
First thing's first, we write out the balanced chemical equation;
2NaOH + H2SO4 --> Na2SO4 + 2H2O
The question hints that sulphuric acid would be in exess by asking to calculate the minium mass that would be left over.
We proceed by calculatng the amount of sulphuric acid that would react with 49.9g of sodium hydroxide.
From the reaction,
2 moles of NaOH reacts with 1 mole of H2SO4.
Calculate moles of sodium hydroxide:
Molar mass of NaOH= 40.0 g/mol
Mass of NaOH = 53 g
moles = Maass / Molar mass = 1.2475
This means 1.2475 would react with x number of moles;
2 = 1
1.2475 = x
x = 1.2475 / 2 = 0.62375
Mass of Sulphuric acid reacted = moles * molar mass = 0.62375 * 98 = 61.1275g
Mimium mass of left over = 94 - 61.1275g = 32.8725g
i tried my hardest and its not aExplanation:
