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avanturin [10]
3 years ago
15

A 10 gram sample of material, a, was placed in water. four grams of it, b, did not dissolve, even after being separated and plac

ed in a second volume of water. bcould not be decomposed into any simpler substances. evaporation of the water from the soluble portion of ayielded 6 grams of solid,
c. heating bin air yielded 8 grams of gas, d, leaving no solid residue. melting and electrolysis of cyielded 2.4 grams of metal, e, and 3.6 grams of gas, f. classify each material described above by placing the corresponding letter in the appropriate place in the table below.
Chemistry
1 answer:
kicyunya [14]3 years ago
3 0
Sksksk isjsjs jsjsjs jsjsjs jsjsjs jsjsjs ksjss
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Green light has a frequency of about 6.00×1014s−1 . What is the energy of a photon of green light?
murzikaleks [220]
3.25 C because I said so and energy is green
8 0
2 years ago
The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:
Nimfa-mama [501]

Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of AgNO_{3} in 50.0 mL of 0.100 M of AgNO_{3}

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= \frac{0.100}{1000}\times 50.0 moles

= 0.00500 moles

According to balanced equation, 1 mol of AgNO_{3} reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of AgNO_{3} react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = (100.0\times 1.00) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= \frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}

= \frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}

= -67716 J/mol

[m = mass, c = specific heat capacity, \Delta T = change in temperature and negative sign is included as it is an exothermic reaction]

4 0
2 years ago
How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?
maw [93]
Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation
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When there is an imbalance in a body system, and the body cannot maintain homeostasis, how might other systems respond?
Ulleksa [173]
Other systems in the body might respond with cramps or overheating, which might eventually kill you, if not taken care of in time. Hope this helps!
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