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avanturin [10]
3 years ago
15

A 10 gram sample of material, a, was placed in water. four grams of it, b, did not dissolve, even after being separated and plac

ed in a second volume of water. bcould not be decomposed into any simpler substances. evaporation of the water from the soluble portion of ayielded 6 grams of solid,
c. heating bin air yielded 8 grams of gas, d, leaving no solid residue. melting and electrolysis of cyielded 2.4 grams of metal, e, and 3.6 grams of gas, f. classify each material described above by placing the corresponding letter in the appropriate place in the table below.
Chemistry
1 answer:
kicyunya [14]3 years ago
3 0
Sksksk isjsjs jsjsjs jsjsjs jsjsjs jsjsjs ksjss
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A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
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Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

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T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

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Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

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