Three examples of arthropods are, a crab, a centipede, and a spider. I know a crab is a arthropod because crabs have an external skeleton. Like armor, it protects the arthropods body. When arthropods are born the exoskeleton is soft but hardens quickly and it can be shed as the creature grows. Arthropods are invertebrates; which means that they do not have a backbone. I also know a centipede is a arthropod because they can have many jointed legs or limbs. Spiders have 8 legs, millipedes can have... Hundreds! I know a spiders are a arthropod because they have a segmented body. This means that they will have a body made up of more than one part. Spiders have two segments and flies have three segments.
-2.5089 kJ is the amount of heat is released by the combustion of the naphthalene.
<h3>How we calculate the released heat?</h3>
Released amount of heat is calculated by using the below formula:
Q = -mcΔT, where
m = mass of naphthalene = 0.25g
c = specific heat of calorimeter = 4.13 kJ/°C
ΔT = change in temperature = 26.43°C - 24°C = 2.43°C
Putting all these values in the above equation, we get
Q = - (0.25 × 4.13 × 2.43) = - 2.5089 kJ
Hence, - 2.5089 kJ heat is released.
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Answer:
<em>Molar mass of the gas is 0.0961 g/mol</em>
<em></em>
Explanation:
The effusion rate of an unknown gas = 11.1 min
rate of effusion = 2.42 min
molar mass of hydrogen = 1 x 2 = 2 g/m
molar mas of unknown gas = ?
From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.
from
=
where
= rate of effusion of hydrogen gas
= rate of effusion of unknown gas
= molar mass of H2 gas
= molar mass of unknown gas
substituting values, we have
=
4.587 =
= /4.587
= 0.31
= = <em>0.0961 g/mol</em>
Answer:
Explanation:
Step 1. Determine the cell potential
<u> </u><u>E°/V</u><u> </u>
2MnO₄⁻ + 16H⁺ + 10e⁻ → 2Mn²⁺+ 8H₂O 1.507
<u>10Cl⁻ ⟶ 5Cl₂ + 10e⁻ </u> <u>-1.358 27
</u>
2MnO₄⁻ + 10Cl⁻ + 16H⁺⟶ 2Mn²⁺ + 5Cl₂ + 8H₂O 0.149
Step 2. Calculate K
The formula relating K and E is
E = 0.149 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C = 298.15 K
n = 10
F = 96 485 C/mol
The value of the equilibrium constant is
The number of molecules= 3.55 x 10²⁴
<h3>Further explanation</h3>
Given
5.9 moles of NaCl
Required
The number of molecules
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
So for 5.9 moles :
= 5.9 x 6.02 x 10²³
= 3.55 x 10²⁴