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Nana76 [90]
3 years ago
5

Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu

re changes from 32 ºC to 57 ºC.
Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

c=2.0769\  \frac{J}{g\ \textdegree C}

Explanation:

-Specific heat capacity is given by the formula:

q=mc\bigtriangleup T

Where:

q is the heat gained or loosed by the substance

m is the mass of the substance

c is the specific heat of the substance

\bigtriangleup T is the change in temperature

#We make c the subject of the formula and substitute to solve for it:

q=mc\bigtriangleup T\\\\c=\frac{q}{m\bigtriangleup T}\\\\\bigtriangleup T=(57-32)\textdegree C=25\textdegree C\\\\\therefore c=\frac{6.75\times 10^4J}{1.3\times 1000\ g\times 25\textdegree  C}\\\\=2.0769 \ \frac{J}{g\ \textdegree C}

Hence, the specific heat capacity of the ice is 2.0769 \frac{J}{g\ \textdegree C}

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Answer: A : Convergent

Explanation:

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3 years ago
What design element of an astronaut's spacesuits protects him or her from micrometeoroids, which are tiny bits of space debris t
leonid [27]

Answer:

Tough outer shell

Explanation:

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3 0
3 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
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Answer:

Explanation:

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8 0
3 years ago
Single covalent bonds are also referred to as ___________.
liubo4ka [24]

Answer:

Single covalent bond are also referred to as sigma bonds

8 0
3 years ago
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