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Brilliant_brown [7]
3 years ago
7

List the two things that affect gravitational force.

Physics
2 answers:
lions [1.4K]3 years ago
4 0
Answer:
Mass and distance affect gravitational force.
777dan777 [17]3 years ago
4 0
The answer to your question is mass and distance
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How long does it take a rocket traveling at a constant velocity of 100 m/s to climb from 200m to 1200m
neonofarm [45]

Answer:

10 seconds

Explanation:

you multiply 100 by 10 in order to get 1000m

you add 200m to 1000m to get to the maximum of 1200m

since you travel at 100 per second, it took 10 seconds

7 0
3 years ago
Dwayne ‘The Rock’ Johnson needs to escape from the fourth floor of a burning building (in a movie). He ties a rope around his wa
ZanzabumX [31]

Answer:

Final Speed of Dwayne 'The Rock' Johnson = 15.812 m/s

Explanation:

Let's start out with finding the force acting downwards because of the mass of 'The Rock':

Dwayne 'The Rock' Johnson: 118kg x 9.81m/s = 1157.58 N

Now the problem also states that the kinetic friction of the desk in this problem is 370 N

Since the pulley is smooth, the weight of Dwayne Johnson being transferred fully, and pulls the desk with a force of 1157.58 N. The frictional force of the desk is resisting this motion by a force of 370 N. Subtracting both forces we get the resultant force on the desk to be: 1157.58 - 370 = 787.58 N

Now lets use F = ma to calculate for the acceleration of the desk:

787.58 = 63 x acceleration

acceleration = 12.501 m/s

Finally, we can use the motion equation:

v^2 - u^2 = 2*a*s

here u = 0 m/s (since initial speed of the desk is 0)

a = 12.501 m/s

and s = 10 m

Solving this we get:

v^2 - 0 = 2 * 12.501 * 10

v = 15.812 m/s

Since the desk and Mr. Dwayne Johnson are connected by a taught rope, they are travelling at the same speed. Thus, Dwayne also travels at            15.812 m/s when the desk reaches the window.

5 0
3 years ago
Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli
GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = k' \frac{q_1 q_2 }{r^2}

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = k \frac{q_1 q_2 }{r^2}

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0
3 years ago
How many electrons are in an element with an atomic number of 20 and an atomic mass of 40? options: ANSWER FOR BRAINLIES
mafiozo [28]

Answer:

B

Explanation:

4 0
3 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
Tju [1.3M]

Answer:

v = 2.85 m/s

Explanation:

By the law of similarity of the triangle we can say

\frac{height\: of\: man}{distance\: of \: man\: from \: spotlight} = \frac{height \:of \:image}{distance\: of \:wall\: from\: spotlight}

here we know that

height of man = 2 m

let the distance of man from spotlight = x

distance of wall from spotlight = 12 m

height of image is let say "y"

so we will have

\frac{2}{x} = \frac{y}{12}

y = \frac{24}{x}

now we have

\frac{dy}{dt} = \frac{24}{x^2}\frac{dx}{dt}

here we know

\frac{dx}{dt} = speed = 1.9 m/s

x = 4 m

now we have

\frac{dy}{dt} = \frac{24}{4^2}(1.9)

v = 2.85 m/s

8 0
4 years ago
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