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Mkey [24]
1 year ago
7

7. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straigh

t
line is showing a constant acceleration?
Physics
1 answer:
guajiro [1.7K]1 year ago
3 0

   An object has positive acceleration if it is accelerating and travelling in the right direction.

<h3>What does it signify if a position time graph has a straight line with a positive slope?</h3>
  • A straight line with a positive slope will appear on the Position vs. Time graph of an item travelling forward at a constant speed. It shows that the object's velocity is constant and that it is travelling ahead.
  • The y-axis of this sort of graph denotes position in relation to the starting point, while the x-axis denotes time. An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph.
  • In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).
  • The starting point of the item is indicated by the y-intercept. An object's y-intercept is zero if it begins at the measuring instrument. Its y-intercept is 3 meters if it begins at a distance of 3 meters. When two items are in the same position, you may tell by where two lines intersect.

To Learn more About Positive acceleration, Refer:

brainly.com/question/460763

#SPJ13

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MakcuM [25]
In an atom, you have three particles: protons, electrons, and neutrons. 

When you add or subtract electrons from an atom, it means that there are either more protons than electrons (positively charged) or there are more electrons than protons (negatively charged).

You cannot add or subtract protons since they are the atomic number, which means the number of protons determines the element. Neutrons have a neutral charge, so they wouldn't affect the charge at all.
8 0
3 years ago
Which disadvantage of nuclear power use poses the greatest threat to the environment?
Mekhanik [1.2K]

The correct answer is The storage and management of radioactive wastes

Explanation:

In general, nuclear reactions (changes in the nucleus of an atom such as fission) release a lot of energy including a lot of heat. Moreover, this heat is used by humans to obtain electricity and other types of energy, which is known as a nuclear power. This type of power is considered positive because it does not emit carbon and it is quite efficient.

However, in most cases, it is a threat to the environment and living beings because storing and managing the wastes of this type of power is difficult and expensive. Indeed, dealing with the wastes of nuclear power requires complex infrastructure, and any accident or leaking leads to serious consequences from the death of those exposed to the wastes to permanent loss of diversity or changes in nearby areas.

6 0
3 years ago
Read 2 more answers
HELP ASAP PLS<br><br> Describe what characterizes science
r-ruslan [8.4K]
Science is characterized by empirical observations, testable questions, formation of hypotheses and experiments that result in stable and replicable results, logic reasoning and theoretical constructs
3 0
3 years ago
Select all that apply
borishaifa [10]
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5 0
3 years ago
A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonc
lisov135 [29]

(a) The tension on the wire when the two charges have opposite signs is 383.5 N.

(b) The tension on the wire if both charges were negative is 3.640.25 N.

The given parameters;

  • <em>first charge, q₁ = 8.75 μC </em>
  • <em>second charge, q₂ = -6.5 μC  </em>
  • <em>electric field, E = 1.85 x 10⁸ N/C</em>
  • <em>distance between the two charges, r = 2.5 cm</em>

<em />

(a)

The attractive force between the charges is calculated as follows;

F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N

The force on the negative charge due to the electric field is calculated as follows;

F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N

The tension on the wire is the resultant of the two forces and it is calculated as follows;

T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N

(b) when the two charges are negative

The repulsive force between the two charges is calculated as follows;

F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N

The force on the first negative charge due to the electric field is calculated as follows;

F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N

The force on the second negative charge due to the electric field is calculated as follows;

F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N

The tension on the wire is the resultant of the three forces and it is calculated as follows;

T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N

Learn more here:brainly.com/question/19565286

5 0
3 years ago
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