Loss of traction between the rear wheels and road surfaces like ice, sand, or gravel results in oversteering.
Fishtailing is considered as a handling problem of a vehicle that occurs whenever traction is lost by the rear wheels which ends in oversteering. This can happen as a result of low friction surfaces including sand, gravel, rain, snow, and ice.
The traction loss of the rear tire can result in a state of oversteer. Whenever the rear tires do not have any grip on the surface of the road, steering a particular car will be having the effect of exaggerated results. Losing of rear wheel traction usually occurs at the time when the brake is applied while driving through a surface of a curved road.
In this case, a drop in the level of speed will be shifting weight into the front tires as it lessens the grip of the rear tire and which causes the rear end to swing out of the turn in opposite direction.
Oversteering is occurred by loss of traction between the rear wheels and road surfaces.
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Answer:
Solar Flares and Prominences
Explanation:
The sun is source of light and heat energy and it supports life on earth because sun is the primary source of energy. But sun is also a star and is a glowing ball of hot gases mostly hydrogen and helium. There are so many activity that takes place on surface of sun. But the two activity solar flare and prominences affect the radio communication.
Solar Flare are electromagnetic energy built up in the sun atmosphere .These energy travel with the speed of light and affect outer atmosphere of earth. These increased level of X rays and ultraviolet rays ions the layer of ionosphere which becomes superionised. thus causing destructive interference.
The radio waves travel in ionosphere and frequently collide with electron lose energy and completely blackout.
Prominence is defined as gaseous cloud of calcium,hydrogen and other gases floating above sun chromosphere and emit violently particularly near sunspots sometimes travel through space and affect radio communication.
initial speed of the stuntman is given as
angle of inclination is given as
now the components of the velocity is given as
here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.
So the displacement in vertical direction is given as
by solving above equation we have
Now in the above interval of time the horizontal distance moved by it is given by
since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.
Reword the questions and you’ll get it right
Answer:
Distance is path length covered by particle. When particle moves along half circle, it covers half the circumference therefore distance covered is (2×pi×r)/2 = pi× r. ... Hence displacement is equal to diameter or 2 times the radius of circle.
