The amount of water needed is 287 kg
Explanation:
The amount of energy that we need to produce with the power plant is

We also know that the power plant is only 30% efficient, so the energy produced in input must be:

The amount of water that is needed to produce this energy can be found using the equation

where:
m is the amount of water
is the specific heat capacity of water
is the increase in temperature
And solving for m, we find:

Learn more about specific heat capacity:
brainly.com/question/3032746
brainly.com/question/4759369
#LearnwithBrainly
Radiation can carry thermal energy.
Answer:
La fuerza que se ejerce entre las dos cargas es 2880 N.
Explanation:
La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

donde:
- F es la fuerza eléctrica de atracción o repulsión. Se mide en Newtons (N).
- Q y q son los valores de las dos cargas puntuales. Se miden en culombios (C).
- r es el valor de la distancia que los separa. Se mide en metros (m).
- k es una constante de proporcionalidad llamada constante de la ley de Coulomb.
En este caso:
- F= ?
- Q= 4*10⁻⁵ C
- q= 2*10⁻⁵ C
- r= 0.05 m
- k= 9*10⁹

Reemplazando:

F= 2880 N
<u><em>La fuerza que se ejerce entre las dos cargas es 2880 N.</em></u>
<u>Answer:</u>
Given Data:
V2 ?
V1 = 200 ml,
P1 = 500kpa and P2 = 2500kpa
From <em>Boyels law</em> (Ideal gas law) Where temperature remains constant, <em>Pressure is inversely proportional to volume.</em>
P1 .V1 = P2 . V2 ; T=Constant
V2 = (P1.V1) ÷ P2
= (500×200) ÷(250)
= 400 ml
<em>The final volume of the gas is 400 ml.</em>
<em>Note: Increased pressure decreases the volume or decreased pressure increase the volume as they are inversely proportional.</em><em> Here in our answer pressure decreases from 500 kpa to 250 kpa so volume increases from 200 ml to 400 ml. </em>
Please find the figure attached below:
Answer:
a.Resistance of bulb=
=192 ohm
b.power consumed by bulb after motor disconnection=74.609 W
Explanation:
<u>a.Resistance of bulb=</u>
<u>=?</u>
As we know that 
putting R as resistance of bulb i.e. 

<u>b.power consumed by bulb after motor disconnection? </u>
from the figure we see that
are in series so

current through their resistance is

Power consumed by bulb is
