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lisabon 2012 [21]
3 years ago
8

A stalled car is being pushed up a hill at constant velocity by three people. The net force on the car is Group of answer choice

s Zero down the hill and greater than the weight of the car. down the hill and equal to the weight of the car up the hill and equal to the weight of the car. up the hill and greater than the weight of the car.
Physics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

Zero

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

Fnet is the net force.

Fapp is the applied force.

Fg is the force due to gravitation.

In this scenario, a stalled car is being pushed up a hill at constant velocity by three people. Thus, the net force on the car is zero because all the forces acting on any physical object is equal to zero and represents a constant velocity; by balancing or cancelling each other out.

According to Sir Isaac Newton's First Law of Motion which is known as Law of Inertia, it states that an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

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MrRa [10]

Answer:

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3 years ago
What is the weight of a 2.06 kg text book. show work please
salantis [7]

The weight of anything is (mass) x (gravity in the place where the thing is).

             Gravity on Earth is about 9.8 newtons per kilogram, so on Earth,
             the weight of the book is

                          (2.06 kg) x (9.8 N/kg) = <em>20.19 newtons</em> .


Another way to get around it is:  

               On Earth, 1 kg of mass weighs about 2.205 pounds, so on earth,
               the weight of the book is

                         (2.06 kg) x (2.205 pounds/kg) = <em>4.54 pounds </em>.


7 0
4 years ago
A surface completely surrounds a 3.3 × 10-6 C charge. Find the electric flux through this surface when the surface is (a) a sphe
KengaRu [80]

Answer:

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Explanation:

given,

surface charge (q) = 3.3 × 10⁻⁶ C

to calculate electric flux = ?

a) radius = 0.76 m

area of sphere = 4 π r²

electric flux = \dfrac{q}{\varepsilon}

\varepsilon = 8.85 \times 10^{-12} C^2/Nm^2

electric flux =  \dfrac{3.3 \times 10^{-6}}{8.85 \times 10^{-12} }

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so, Electric flux in a) , b) and c) is same which is   0.373 × 10 ⁶ N m²/C

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Answer:

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Explanation:

The best statement to describe Energy is:

"The capacity of a system to perform work of any type."

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