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3 years ago

In what way are gravitational and electrical forces similar?

Physics

1 answer:

Nadusha1986 [10]3 years ago

6 0

Answer:

D. Both occur between objects independently whether they are in contact or not.

Explanation:

- The gravitational force is a force that is exerted between two (or more) objects having mass. This force is always attractive and its magnitude is given by

$F=G\frac{m_1 m_2}{r^2}$

where G is the gravitational constant, m1 and m2 are the two masses, and r is the distance between the two masses.

- The electrical force is a force that is exerted between two (or more) objects having electrical charge. It can be either attractive or repulsive, depending on the sign of the two charges, and its magnitude is given by

$F=k\frac{q_1 q_2}{r^2}$

where k is the Coulomb's constant, q1 and q2 are the two charges, and r the distance between the two charges.

Looking at both formulas, we see that the two forces are present even when the two objects are not in contact with each other (in fact, r can assume any value in the formula). They are said to be non-contact forces. Therefore, the correct option is

D. Both occur between objects independently whether they are in contact or not.

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The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f

Hoochie [10]

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3 years ago

X-rays with an energy of 86 keV scatter off of stationary electrons. How much energy do the photons scattering at 60° have? A. 7

AveGali [126]

Answer:

A. 79.3 keV

Explanation:

Because the procedure involves many steps for its resolution and it works faster on paper and pencil, the detailed solution of this exercise is attached as a scanned image of the procedure for review.

In the procedure, the initial values of the problem and the replacement of these values with the correct formulas for this process are taken into account.

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3 years ago

A bowling ball (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as un

Semenov [28]

Answer:

Explanation:

Given that

Mass of bowling ball M1=7.2kg

The radius of bowling ball r1=0.11m

Mass of billiard ball M2=0.38kg

The radius of the Billiard ball r2=0.028m

Gravitational constant

G=6.67×10^-11Nm²/kg²

The magnitude of their distance apart is given as

r=r1+r2

r=0.028+0.11

r=0.138m

Then, gravitational force is given as

F=GM1M2/r²

F=6.67×10^-11×7.2×0.38/0.138²

F=9.58×10^-9N

The force of attraction between the two balls is

F=9.58×10^-9N

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3 years ago

Question: How is a triple beam balance used to find mass?1. Observe: The riders have masses of 10 grams (top), 100 grams (middle

ozzi

Answer:

1) For the weight to be correct, the pointer must be below the reference (zero) or in it

2) mass greater than 300 g leave the pointer below the reference,

3) put weight on the other arms the pointer gets closer to the reference

Explanation:

1) A three-arm scale is used to determine the weight of a body by successive approximations, starting with the arm with the greatest mass (middle), when the pointer is close to zero without going over, weights are placed on the second arm (above ) weight is placed to bring the pointer closer to the reference without going over and when it is used the arm with the lowest mass is used (below) with this one, masses are placed until reaching the reference,

Taking all the jinetillos placed the total weight, the product of the position of the jinetillo by the precision of the arm and then the three values are added.

In the example given, the jinetillo is placed in position 3 of the 100 arm, so the weight is 300 gr.

For the weight to be correct, the pointer must be below the reference (zero) or in it

2) objects with a mass greater than 300 g leave the pointer below the reference, it must be completed with the other two arms to reach the correct weight

3) when you put weight on the other arms the pointer gets closer to the reference

4 0

4 years ago

8. Object A has a momentum of 80 Ns and collides and sticks to object B which has a momentum of -30 Ns. What is the momentum of

BigorU [14]

Given,

The momentum of the object A before the collision, p₁ =80 Ns

The momentum of the object B before the collision, p₂=-30 Ns

Given that the objects stick together after the collision.

From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.

Thus,

$p_1+p_2=p$

Where p is the total momentum of the system at any instant of time.

On substituting the known values,

$\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}$

Therefore the total momentum of the system is 50 Ns

Thus the momentum of the object AB after the collision is 50 Ns

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1 year ago