<u>what's</u><u> </u><u>your </u><u>question </u><u>O_</u><u>-</u><u> </u><u>?</u><u>?</u>
<u>you </u><u>have </u><u>given</u><u> </u><u>the</u><u> </u><u>es</u><u>s</u><u>ay,</u><u> </u><u>but </u><u>wts </u><u>the </u><u>topic </u><u>?</u><u> </u><u>lol</u>
in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.
your temp should be converted in kelvin
variables:
p1=3.0×10^6 n/m^2
t1= 270k
just add 273 to your celcius
p2= ? your solving for this
t2= 315k
then you set up the equation
(3.0×10^6)/270= (x)(315)
you then cross multiply
(3.0×10^6)315=270x
distribute the 315 to the pressure.
9.45×10^8=270x then you divide 270 o both sides to get
answer
3.5×10^6 n/m^2
1200
-------=171 miles per hour
7
1.) when the distance between the two objects is dubled then the gravitational Force btw them is <u>reduced by 4 times</u> I.e it becomes 1/4 of original due to the <u>inverse square law.</u>
2.) because the distance from the center of earth and pole is less then the distance btw pole and equator that's why due to <u>inverse square law</u> .
the gravitational Force on object at equator is less then the object on poles.