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Rufina [12.5K]
3 years ago
10

A hockey puck is pushed by a stick with a force of 750 newtons. The puck travels 2.0 meters in 0.30 seconds. How powerful is the

push?
1,500 W
5,000 W
112 W
450 W
Physics
2 answers:
Tamiku [17]3 years ago
6 0

The work done to push the puck is the product between the force F and the distance d:

W=Fd=(750 N)(2.0 m)=1500 J


And the power is the work done (W) per unit time (t):

P=\frac{W}{t}


Substituting the work done, W=1500 J, and the time taken, t=0.30 s, we find the power of the push:

P=\frac{1500 J}{0.30 s}=5000 W



lubasha [3.4K]3 years ago
6 0
Power, P = Force, F * Velocity, V

V = distance/time = 2/0.3 = 6.67 m/s

Therefore,
P = 750*6.67 = 5000 W

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The equilibrium condition allows finding the results for the forces of the system are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition

          ∑ F = 0

Where the bold letters indicate vectors, F is the external forces

a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.

b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force

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Let's apply the equilibrium condition

                N -  W_m -w_{table} = 0

                N =  W_m +w_{table}

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They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N

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c) To calculate the mass of the table we use the relation

                W = m_{table} g

                m_{table} = \frac{w_{table}}{g}

                m_{tabble}= \frac{100}{9.8}  

               m_{table}e = 10.2 kg

In conclusion using the equilibrium condition we can find the results for the forces are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Learn more here:  brainly.com/question/19860811

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Answer:

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