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Mamont248 [21]
1 year ago
14

Under constant pressure a sample of hydrogen gas initially at 88°C and 9.6 L is cooled until its final volume is 3.4 L. What is

the final temperature?
Chemistry
1 answer:
Scilla [17]1 year ago
7 0

The final temperature = -145.24K or 127°C.

According to the data given,

T1= 88°C = 361.15K

V1= 9.6 L

V2= 3.4 L

T2= ?

We know that, according to Charles's law,

T1/V1=T2/V2

T2= T1*V2/V1

T2= 127°C or -145.24K

The final temperature = -145.24K or 127°C

<h3>What does Charles law state?</h3>

According to Charles' law, when the pressure is held constant, the volume of a given amount of gas is precisely proportional to its temperature on the kelvin scale.

<h3>What connection exists between volume and temperature?</h3>
  • In layman's words, the volume of a fixed mass of gas is exactly proportional to temperature at constant pressure.
  • When a constant mass of gas is cooled, its volume decreases, and when the temperature is elevated, its volume grows.

<h3>What are the applications of Charles law?</h3>
  • A hot air balloon drifting through the air is an illustration of Charles Law in action.
  • The air within the balloon is heated by a torch, which causes the air molecules to move more quickly and disperse.
  • This causes the air inside the balloon to be less dense than the air outside, which causes the balloon to float.

To learn more about Charles law visit:

brainly.com/question/16927784

#SPJ9

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Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

6 0
3 years ago
Alex dragged a log across the yard in 30 the log weighted 400n she did 900 j of work how much power did I she have
In-s [12.5K]

The power used by Alex to drag the log across the yard is determined as 2,656 W.

<h3>Mass of the log</h3>

The mass of the log is calculated as follows;

W = mg

m = W/g

m = (400)/9.8

m = 40.82 kg

<h3>Velocity of the log</h3>

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 900)/(40.82)

v² = 44.096

v = 6.64 m/s

<h3>Power used by Alex</h3>

P = Fv

P = 400 x 6.64

P = 2,656 W

Learn more about power here: brainly.com/question/13881533

#SPJ1

5 0
2 years ago
Write the balanced neutralization reaction that occurs between h2so4 and koh in aqueous solution. Phases are optional.
Nutka1998 [239]

Answer:

The answer to your question is below

Explanation:

H₂SO₄ = sulphuric acid

KOH = potassium hydroxide

This is a neutralization reaction

                       H₂SO₄   +  2 KOH   ⇒     K₂SO₄   +  2H₂O

                                 2 -----------   K  ----------- 2

                                 1 -----------   S  ----------  1

                                 4 ----------   H  ---------   4

                                6 ------------   O ----------  6

4 0
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In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
Yuliya22 [10]
The balanced chemical equation is:

2H2 + O2 ---> 2H2O

We are given the amount of the product produced from the reaction. This will be the starting point for the calculations.

355 g H2O ( 1 mol H2O/ 18.02 g H2O) ( 1 mol O2 / 2 mol H2O ) ( 32 g O2 / 1 mol O2 ) = 315.205 g O2
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Which force is a contact force
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Answer:

B. a bike braking

Explanation:

It involves friction! Hope this helps!

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