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Mamont248 [21]
1 year ago
14

Under constant pressure a sample of hydrogen gas initially at 88°C and 9.6 L is cooled until its final volume is 3.4 L. What is

the final temperature?
Chemistry
1 answer:
Scilla [17]1 year ago
7 0

The final temperature = -145.24K or 127°C.

According to the data given,

T1= 88°C = 361.15K

V1= 9.6 L

V2= 3.4 L

T2= ?

We know that, according to Charles's law,

T1/V1=T2/V2

T2= T1*V2/V1

T2= 127°C or -145.24K

The final temperature = -145.24K or 127°C

<h3>What does Charles law state?</h3>

According to Charles' law, when the pressure is held constant, the volume of a given amount of gas is precisely proportional to its temperature on the kelvin scale.

<h3>What connection exists between volume and temperature?</h3>
  • In layman's words, the volume of a fixed mass of gas is exactly proportional to temperature at constant pressure.
  • When a constant mass of gas is cooled, its volume decreases, and when the temperature is elevated, its volume grows.

<h3>What are the applications of Charles law?</h3>
  • A hot air balloon drifting through the air is an illustration of Charles Law in action.
  • The air within the balloon is heated by a torch, which causes the air molecules to move more quickly and disperse.
  • This causes the air inside the balloon to be less dense than the air outside, which causes the balloon to float.

To learn more about Charles law visit:

brainly.com/question/16927784

#SPJ9

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Complete combustion of 7.50 g of a hydrocarbon produced 23.1 g of CO2 and 10.6 g of H2O. What is the empirical formula for the h
r-ruslan [8.4K]
A CH compound is combusted to produce CO2 and H2O 
CnHm + O2 -----> CO2 + H2O 
Mass of CO2 = 23.1g
 Mass of H2O = 10.6g
 Calculate by mass of the compounds
 For Carbon C, divide by molecular weight of CO2 and multiply with Carbon
molecular weight. So C in grams = 23.1 x (12.01 / 44.01) = 6.3 g C
 For Hydrogen H, divide by molecular weight of H2O and multiply with Hydrogen molecular weight. So H in grams = 10.6 x (2.01 / 18.01) = 0.53 g C
= 1.18 of H
 Calculate the moles for C and H
 6.3 grams of C x (1 mole/12.01 g C) = 0.524 moles of C
 1.18 grams of H x (1 mole/1.008 g H) = 1.17 moles of H
 Divides by both mole entities with smallest
 C = 0.524 / 0.524 = 1 x 4 = 4
 H = 1.17 / 0.524 = 2.23 x 4 = 10
 The empirical formula is C4H10.
7 0
3 years ago
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10) One mole of a diatomic ideal gas is initially at a temperature of 127 °C and
Vladimir79 [104]
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6 0
3 years ago
Ce cantitate de O se gaseste in 5,8 g hidroxid de magneziu
coldgirl [10]

Answer:

separare pâlnii de picurare balon cotat. 1. 2. 3. 4 5 6 7. 8. 9. 1 ... Mod de lucru: 25 g Na2SO4∙7H2O se dizolvă în cantitatea minim ... Exemple: NaOH – hidroxid de sodiu.

Explanation:

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4 0
4 years ago
How many moles of O2 are required to generate 18 moles of H2O in the given reaction? 2C8H18 + 25O2 16CO2 + 18H2O
Veronika [31]
There's a slight error in your equation. I think you were trying to present it like this:

2C8H18 + 25O2 -> 16CO2 + 18H2O

Mole Ratio
O2 : H20
25 : 18
? moles : 18 moles
(18/18)×25 : 18 moles

25 moles : 18 moles

Final answer would be 25 moles of O2. :)

If you have any doubts that you want to clarify with me, please ask me! :)
I will do my utmost best to help you.
7 0
4 years ago
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An aqueous potassium carbonate solution is made by dissolving 5.51 moles of K 2 CO 3 in sufficient water so that the final volum
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Answer:

1.67mol/L

Explanation:

Data obtained from the question include:

Mole of solute (K2CO3) = 5.51 moles

Volume of solution = 3.30 L

Molarity =?

Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:

Molarity = mole of solute /Volume of solution

Molarity = 5.51 mol/3.30 L

Molarity = 1.67mol/L

Therefore, the molarity of K2CO3 is 1.67mol/L

3 0
3 years ago
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