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valentinak56 [21]
3 years ago
5

What are the major products when glucose is broken down in glycolysis? NAD+ and FAD ATP and NADH ATP, FADH2, and NADH pyruvic ac

id and ATP
Chemistry
2 answers:
Alexxandr [17]3 years ago
7 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

Glycolysis is the first which is same in both aerobic and anaerobic respiration.

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It is occur in cytosol of living organisms. In human body, glycolysis produce pyruvate in aerobic condition while lactic acid is produced in anaerobic condition. In aerobic process one molecule of glucose is converted into two molecule of pyruvate and two ATP also produced. The two NADH are also produced as a result of oxidation of pyruvate.

The overall reaction can be written as,

C₆H₁₂O₆ + 2NAD⁺ + 2Pi + 2ADP → 2Pyruvate + 2NADH + 2ATP + 2H⁺ + 2H₂O

morpeh [17]3 years ago
4 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

my brain did science

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6 0
3 years ago
If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
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The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

Learn more about pH here:

brainly.com/question/24595796

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