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valentinak56 [21]
3 years ago
5

What are the major products when glucose is broken down in glycolysis? NAD+ and FAD ATP and NADH ATP, FADH2, and NADH pyruvic ac

id and ATP
Chemistry
2 answers:
Alexxandr [17]3 years ago
7 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

Glycolysis is the first which is same in both aerobic and anaerobic respiration.

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It is occur in cytosol of living organisms. In human body, glycolysis produce pyruvate in aerobic condition while lactic acid is produced in anaerobic condition. In aerobic process one molecule of glucose is converted into two molecule of pyruvate and two ATP also produced. The two NADH are also produced as a result of oxidation of pyruvate.

The overall reaction can be written as,

C₆H₁₂O₆ + 2NAD⁺ + 2Pi + 2ADP → 2Pyruvate + 2NADH + 2ATP + 2H⁺ + 2H₂O

morpeh [17]3 years ago
4 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

my brain did science

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AleksAgata [21]
I think the answer would be trenches but I’m sorry if I’m wrong
4 0
3 years ago
Calculate the molar mass of menthol, C10H20O
Cerrena [4.2K]

Answer:

C10H200

Explanation:

The molecular formula C10H20O (molar mass : 156.27 g/mol) may refer to: Citronellol. Decanal.

7 0
2 years ago
In the science fiction movie, The Abyss, a diver is able to breathe while his head is immersed in a specially prepared liquid pu
Klio2033 [76]

Answer:

Explanation:

This type of experiment was carried out in 1960s on rodents, it was partially successful but was perceived impractical and dangerous for humans,it is possible theoretically.

Oxygen is broken down or dissolves in a thin film of fluid in the alveoli, surprisingly in normal breathing liquid composed of dissolved oxygen is involved. Evidently respiratory gas must be able to dissolve in this liquid and in concentration required to keep the partial pressure necessary to power diffusion.

5 0
3 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
3 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH}  =0.1900gO

4. Compute the moles of oxygen by using its molar mass:

n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1

6. Search for the closest whole number (in this case multiply by 2):

C_3H_6O_2

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

M=12*3+1*6+16*2=74g/mol

Which is about three times in the molecular formula, for that reason, the actual formula is:

C_9H_{18}O_6

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0
3 years ago
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