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valentinak56 [21]
3 years ago
5

What are the major products when glucose is broken down in glycolysis? NAD+ and FAD ATP and NADH ATP, FADH2, and NADH pyruvic ac

id and ATP
Chemistry
2 answers:
Alexxandr [17]3 years ago
7 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

Glycolysis is the first which is same in both aerobic and anaerobic respiration.

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It is occur in cytosol of living organisms. In human body, glycolysis produce pyruvate in aerobic condition while lactic acid is produced in anaerobic condition. In aerobic process one molecule of glucose is converted into two molecule of pyruvate and two ATP also produced. The two NADH are also produced as a result of oxidation of pyruvate.

The overall reaction can be written as,

C₆H₁₂O₆ + 2NAD⁺ + 2Pi + 2ADP → 2Pyruvate + 2NADH + 2ATP + 2H⁺ + 2H₂O

morpeh [17]3 years ago
4 0

Answer:

NADH, pyruvic acid and ATP

Explanation:

my brain did science

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<u>Answer:</u>

The correct answer option is a. Selenium (Se).

<u>Explanation:</u>

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It changed from unsaturated to saturated solution

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A 100.0 g sample of aluminum released 1680 calories when cooled from 100.0c to 20.0 c what is the specific heat of the metal
vovangra [49]

Answer:

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Explanation:

Step 1 : Write formule of specific heat

Q=mcΔT

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

with ΔT = Change in temperature

For this case :

Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)

m = 100.0g

c= has to be determined

ΔT = 100 - 20 = 80°C

<u>Step 2:  Calculating specific heat</u>

⇒ via the formule Q=mcΔT

7033.824 J = 100g * c * 80

7033.824 = 8000 *c

c = 7033.824 /8000

c = 0,879228 J/g °C

or 0.21 Cal / g°C

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

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