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Ad libitum [116K]
2 years ago
12

HELP ASAP!! if given the following balanced equation, circle one of the following calculations that shows how to correctly deter

mine the amount of CO2 gas (in moles) that will be produced if you start with 6 moles of calcium carbonate CaCO3

Chemistry
1 answer:
bekas [8.4K]2 years ago
3 0

Answer:

The answer is B.

Explanation:

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Calculate Density:<br> Volume=13cm3, Mass=147.55g<br> Someone please help
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11.35 g/cm³

Explanation:

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Which formula represents copper(I) oxide?<br> (1) CuO (3) Cu2O<br> (2) CuO2 (4) Cu2O2
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3 years ago
In a titration, 4.7 g of an acid (HX) requires 32.6 mL of 0.54 M NaOH(aq) for complete reaction. What is the molar mass of the a
katrin2010 [14]

Answer : The molar mass of an acid is 266.985 g/mole

Explanation : Given,

Mass of an acid (HX) = 4.7 g

Volume of NaOH = 32.6 ml = 0.0326 L

Molarity of NaOH = 0.54 M = 0.54 mole/L

First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

\text{Moles of an acid}=\frac{\text{Mass of an acid}}{\text{Molar mass of an acid}}

Now put all the given values in this formula, we get:

0.017604mole=\frac{4.7g}{\text{Molar mass of an acid}}

\text{Molar mass of an acid}=266.985g/mole

Therefore, the molar mass of an acid is 266.985 g/mole

3 0
3 years ago
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