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I am Lyosha [343]
3 years ago
11

Two compounds are tested for mass composition. Compound X contains 15.0 grams hydrogen and 120.0 grams oxygen. Compound Y contai

ns 2.0 grams of hydrogen and 32.0 grams of oxygen. Are compound X and compound Y the same compound?
Chemistry
1 answer:
4vir4ik [10]3 years ago
3 0
In order to determine if compounds X and Y are the same, the mole percentages of the elements present should be equal in both compounds.

For compound X

number of moles H = 15/ 1 =15 mol H
number of moles O = 120/ 16 = 7.5 mol O

total moles = 22.5 mol

mole percentages
% mole H = 67%
% mole O = 33%

For compound Y 

mole of H = 2 /1 = 2
mole of O = 32/16 = 2

total mole = 4 mole

mol %

% mol H = 50%
% mol O = 50%

there the two compounds are not the same.
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A gas has a density of 1.57 g/L at 40.0 °C and 2.00 atm of pressure. What is the identity of the gas?
Naddika [18.5K]

Answer:

Neon

Explanation:

Step 1: Given and required data

  • Density of the gas (ρ): 1.57 g/L
  • Temperature (T): 40.0°C
  • Pressure (P): 2.00 atm
  • Ideal gas constant (R): 0.08206 atm.L/mol.K

Step 2: Convert T to Kelvin

We will use the following expression.

K = °C + 273.15 = 40.0 + 273.15 = 313.2 K

Step 3: Calculate the molar mass of the gas (M)

For an ideal gas, we will use the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 1.57 g/L × 0.08206 atm.L/mol.K × 313.2 K/2.00 atm

M = 20.17 g/mol

The gas with a molar mass of 20.17 g/mol is Neon.

6 0
2 years ago
How much time would it take to distribute one avagadro's number of wheat grains if 10^10 grains are A)1.9*10^2 years B)1.9*10^10
Makovka662 [10]

Answer:

It takes  1.9 \times 10^{6} years to distribute all the grains.

Explanation:

In one second, 10^{10} grains of wheat are distributed.

We are supposed to find the time it would take to Distribute Avogadro number of grains.

1 avogadro number = 6.022 \times 10^{23}

Number of grains distributed in 1 day = 86400 \times 10^{10}

                                                             = 8.64 \times 10^{14}

Number of grains distributed in 1 year= 8.64 \times 10^{14} \times 365

                                 = 3.1536 \times 10^{17}

Time taken = \frac{Number of grains to be distributed}{grains distributed in 1 year}

            = \frac {6.022 \times 10^{23}}{3.1536\times 10^{17}}

            = 1.9 \times 10^{6}

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Explanation:

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