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elena55 [62]
1 year ago
15

What force causes centripetal acceleration of a car making a turn on a flat road?

Physics
1 answer:
Stella [2.4K]1 year ago
3 0

The force that causes centripetal acceleration of a car making a turn on a flat road is friction

The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.

Fc = f

m v² / r = μ N

Fc ∝ 1 / r

The larger the centripetal force the the smaller the radius of curvature.

Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction

To know more about centripetal force

brainly.com/question/11324711

#SPJ9

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dangina [55]
I’m confused what exactly your question is?
8 0
3 years ago
True or false. On a distance-versus-time graph, a speed of zero would appear as a horizontal line.
lidiya [134]

Yes, that's a true statement.

The slope of a distance-time graph is speed.  When speed is zero,
the slope of the graph is zero, and that's a horizontal line.

5 0
4 years ago
Read 2 more answers
Question 6 (2 points)
LenKa [72]

Answer:

A. increase the speed

Explanation:

For you to be able to shorten the time it takes for the care to get to its destination, you must increase the speed because if the distance is the same that means you have to increase your speed.

3 0
3 years ago
11) The total conversion of 2.50 kilogram of the
Elanso [62]

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

⇒1.41 × 10³⁰ MeV

If you want to learn more about mass-energy conversions then you can check out this link:

https://brainly.in/question/9760064

3 0
2 years ago
Read 2 more answers
A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
marin [14]

Answer:

T=66262.4s

Explanation:

From the question we are told that:

Altitude A=2.90 *10^7

Mass m=5.97 * 10^{24} kg

Radius r=6.38 *10^6 m.

Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

V=3354.83m/s

Therefore

Period T is Given as

T=\frac{2 \pi *a}{V}

T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}

T=66262.4s

4 0
3 years ago
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