His weight on the moon would be less due to gravity and i also believe during your time under little gravity your spine decompresses so you get taller <span />
        
                    
             
        
        
        
By definition, Ampere is a unit of current which is a measure of the amount of charge passing through a point in a circuit per unit  of time, with an equivalent charge of 1.602 x 10^(-19) Coulomb per electron. To determine the number of electrons passing through the heater, we use the definition of the current. We calculate as follows:
13.5 A = 13.5 C per second
Charge = 13.5 C/s (10 min) ( 60 s / 1 min)
Charge = 8100 C 
Number of electrons = 8100 C / 1.602 x 10^(-19) C per electron
Number of electrons = 5.1 x 10^22 electrons
Therefore, there are 5.1 x10^22 electrons that assed through the heater for 10 minutes.
        
             
        
        
        
Answer:
Option B:
A child sitting on a swing.
Explanation:
When we hear the word oscillator, a good example is the pendulum bob of a grandfather clock. We can picture the motion to get a perfect understanding of its path of motion and relate it to other systems of motion in our everyday life.
An oscillator is a system that moves in such a way that it reverses its direction after a period of time. It can be seen as a "to-and-fro" motion.
From the options, a child sitting on a swing is the perfect example of an oscillating system because the child will be moving forwards and backwards, alternately reversing the direction of motion with time.
 
        
             
        
        
        
Answer:
PE= m * g *h
work:
PE= 65kg * 9.8 kg *8,800 m
PE=5605600 m/kg
idk the actual units i forgot
 
        
             
        
        
        
Answer:
 a = 17.68 m/s²
Explanation:
given,
length of the string, L = 0.8 m
angle made with vertical, θ = 61°
time to complete 1 rev, t = 1.25 s
radial acceleration = ?
first we have to calculate the radius of the circle
  R = L sin θ
  R = 0.8 x sin 61°
  R = 0.7 m
now, calculating at the angular velocity 
 
 
   ω = 5.026 rad/s
now, radial acceleration
  a = r ω²
  a = 0.7 x 5.026²
  a = 17.68 m/s²
hence, the radial acceleration of the ball is equal to 17.68 rad/s²