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elena55 [62]
1 year ago
15

What force causes centripetal acceleration of a car making a turn on a flat road?

Physics
1 answer:
Stella [2.4K]1 year ago
3 0

The force that causes centripetal acceleration of a car making a turn on a flat road is friction

The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.

Fc = f

m v² / r = μ N

Fc ∝ 1 / r

The larger the centripetal force the the smaller the radius of curvature.

Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction

To know more about centripetal force

brainly.com/question/11324711

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A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
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Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

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4 years ago
John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. He is pulling horizontally wi
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Answer:

The mass of Laura and the sled combined is 887.5 kg

Explanation:

The total force due to weight of Laura and friction on the sled can be calculated as follows;

F_T = F_L+F_S

     = (400 + 310) N

     = 710 N

From Newton's second law of motion, "the rate of change of momentum is directly proportional to the applied force.

F_T = \frac{(M_L+M_S)V}{t}

where;

M_L is mass of Laura and

M_S is mass of sled

Mass of Laura and the sled combined is calculated as follows;

(M_L+M_S) = \frac{F_T*t}{V}

given

V = Δv = 4-0 = 4m/s

t = 5 s

(M_L+M_S) = \frac{710*5}{4}\\\\(M_L+M_S) =  887.5 kg

Therefore, the mass of Laura and the sled combined is 887.5 kg

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