All categories

10 months ago

What force causes centripetal acceleration of a car making a turn on a flat road?

Physics

1 answer:

Stella [2.4K]10 months ago

3 0

The force that causes centripetal acceleration of a car making a turn on a flat road is friction

The centripetal acceleration is required to create a centripetal force. The centripetal force that cause an object to turn in a circular path is due to the force of friction between the tyres and the road. The magnitude of centripetal force is numerically equal to the magnitude of frictional force.

Fc = f

m v² / r = μ N

Fc ∝ 1 / r

The larger the centripetal force the the smaller the radius of curvature.

Therefore, the force that causes centripetal acceleration of a car making a turn on a flat road is friction

To know more about centripetal force

brainly.com/question/11324711

#SPJ9

You might be interested in

Match these names with the correct statements. 1. said sun revolved around earth Clyde Tombaugh 2. said earth revolved around su

Murljashka [212]

Answer:

1. Ptolemy.

2. Nicolaus Copernicus.

3. Tycho Brahe

4. Galileo Galilei

5. Isaac Newton

6. William Herschel

7. Johann Galle

8. Clyde Tombaugh

9. Albert Einstein.

10. Edwin Hubble

11. Karl Jansky.

12. Grote Weber.

Explanation:

1. Ptolemy: said sun revolved around earth.

2. Nicolaus Copernicus: aid earth revolved around sun.

3. Tycho Brahe: analyzed motions of planets.

4. Galileo Galilei: first used refracting telescope for astronomy.

5. Isaac Newton: invented reflecting telescope.

6. William Herschel: discovered the planet Uranus.

7. Johann Galle: discovered the planet Neptune.

8. Clyde Tombaugh: discovered the dwarf planet Pluto.

9. Albert Einstein: developed special and general theories of relativity.

10. Edwin Hubble: demonstrated that universe is expanding.

11. Karl Jansky: discovered radio waves from the center of the Milky Way.

12. Grote Weber: an amateur astronomer who built the first radio telescope.

8 0

3 years ago

What would be the current going through a 200 ohm resister that is connected across a 120 v power supply?

gavmur [86]

Here is your answer

hope it help you

6 0

3 years ago

10. A diver is collecting shells under water. They see a very large and beautiful shell so they reach out to pick it up. After s

dexar [7]

Answer:

It is the depth of the water that allowed it to be like day

Explanation:

what we see abovewater is not the actual thing or ssize we would see when insife the water

4 0

1 year ago

What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

6 0

3 years ago

Read 2 more answers

The star Antares has an apparent magnitude of 1.0, whereas the star Procyon has an apparent magnitude of 0.4. Which star appears

Anika [276]

Answer:

Procyon appears brighter in the sky

Explanation:

Apparent magnitude of star Antares = 1.0

Apparent magnitude of star Procyon = 0.4

Pogson's Ratio

m₂-m₁ = -2.50 log(B₂/B₁)

where, m is the apparent magnitude

B = Brightness of star or flux coming towards us (W/m²)

∴Larger magnitudes correspond to fainter stars so here 1>0.4 which means Antares appears dimmer and Procyon appears brighter.

6 0

3 years ago