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Bingel [31]
2 years ago
6

1. A 61-kg woman doing pull-ups lifts her body a distance of 0.32 meters in 1.8 seconds. What is the power provided by her bicep

s?
Physics
1 answer:
Allushta [10]2 years ago
4 0

Answer:

P = mgh/t = 61(9.8)(0.32)/1.8 = 106.275555... ≈ 110 W

Explanation:

Power is the rate of doing work.

The work changes her potential energy.

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Answer:

H = 3.9 m

Explanation:

mass (m) = 48 kg

initial velocity (initial speed) (U) = 8.9 m/s

final velocity (V) = 1.6 m/s

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find the height she raised her self to as she crosses the bar (H)

from energy conservation, the change in kinetic energy = change in potential energy

0.5m(V^{2} - [test]U^{2}[/tex]) = mg(H-h)

where h = initial height = 0 since she was on the ground

the equation becomes

0.5m(V^{2} - [test]U^{2}[/tex]) = mgH

0.5 x 48 x (1.6^{2} - [test]8.9^{2}[/tex]) = 48 x 9.8 x H

-1839.6 = 470.4 H  (the negative sign indicates a decrease in kinetic energy so we would not be making use of it further)

H = 3.9 m

4 0
3 years ago
When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?
Inessa [10]

When a mirror is rotated . . .

-- The incident ray doesn't turn.  It's just the line from the source to the mirror. 
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with the mirror.

-- Since the normal tuns and the incident ray doesn't, the angle between them
must change.  And since the angle of the reflected ray is equal to the angle of
the incident ray, the reflected ray must also turn.


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Answer:

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Explanation:

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