Answer:
ages would no longer get larger as the mouse hovers over them. The transition would happen over 10s, since this is the default duration.
Step-by-step explanation:
<span>7x-4y=-7
5x+y=22
multiply 4 on the 2nd equation
</span>20x+ 4y=88
now you have
7x -4y = -7
20x + 4y = 88
--------------------add
27x = 81
x = 3
7x-4y=-7
7(3)-4y=-7
-4y = -28
y = 7
answer (3, 7) is the solution
Answer:
20a + -5b + -9
Step-by-step explanation:
Answer:
<u>The lengths of side A is 22.4 and B is 11.9</u>.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be
So, the side A be
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²
<em>Dividing both sides by 5 we get:</em>
<em>Using square root on both sides we get:</em>
<u>B rounding to the nearest tenth = 11.9.</u>
Now, to get A by substituting the value of :
<u>A rounding to the nearest tenth = 22.4.</u>
Therefore, the lengths of side A is 22.4 and B is 11.9.
Answer:
See below
Step-by-step explanation:
Vertical velocity will be affected by gravity in this scenario
df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2
<u>df = 4 + 89 t - 1/2 (32.2) t^2 df = height</u>
<u />
On the way up and the way down, the ball may reach height of 102.2125 ft :
102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:
-16.1 t^2 + 89t - 98.2125 =0
Use Quadratic Formula to find <u>t = 1.5 and 4.0 s </u>