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WARRIOR [948]
1 year ago
8

this is the chemical formula for methyl tert-butyl ether (the clean-fuel gasoline additive mtbe):a chemical engineer has determi

ned by measurements that there are moles of carbon in a sample of methyl tert-butyl ether. how many moles of oxygen are in the sample?be sure your answer has the correct number of significant digits
Chemistry
1 answer:
Alex17521 [72]1 year ago
6 0

The Number of moles required for MTBE is 2 as per molarity based chemistry theories.

  1. A flammable liquid with a distinct, unpleasant smell is called methyl tert-butyl ether (MTBE).
  2. Since the 1980s, it has been added to unleaded gasoline as a fuel additive to promote more effective burning.
  3. It is created by mixing chemicals like isobutylene and methanol. Gallstones can be removed with MTBE as well.
  4. In this type of treatment, surgically inserted special tubes are used to deliver MTBE directly to the gall bladders of the patients.
  5. Methyl tert-butyl ether is a colorless liquid with a distinct anesthetic-like smell. Vapors are narcotic and heavier than air. 131 °F boiling point. 18 °F is the flash point.
  6. It is miscible in water and less dense than water. Boosts the octane of gasoline.
  7. Therefore it has 2 moles of oxygen.

To study about isobutylene -

<u>brainly.com/question/8409160</u>

#SPJ4

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what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
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Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

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