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kicyunya [14]
1 year ago
8

Is annealed polycrystalline copper a material that work hardens significantly or a material that exhibits a low work-hardening r

ate
Engineering
1 answer:
Olegator [25]1 year ago
6 0

Those that harden under strain, such as the aluminum-magnesium alloys used in beverage cans and the copper-zinc alloy, brass, used for cartridges, which show more strain hardening than pure copper or aluminum, respectively.

When a material is deformed under a substantial amount of strain, strain hardening is seen as a strengthening process. Lamellar crystals and chain molecule orientation on a vast scale are the culprits. When plastic materials are stretched past their yield point, this phenomena is frequently seen. When a metal is stretched past its yield point, strain hardening occurs. The metal appears to get stronger and harder to deform as more stress is needed to cause additional plastic deformation. Strain hardening is directly related to fatigue.

Learn more about strain hardening here-

brainly.com/question/15058191

#SPJ4

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1. A soil core sampling tube of 4 cm diameter, 12 cm length and initial mass of 0.525 kg (sample only), was dried at 105o C and
belka [17]

Answer:

porosity = 0.07 or 7%

dry bulk density = 3.25g/cm3]

water content =

Explanation:

bulk density = dry Mass / volume of  sample

dry mass = 0.490kg = 490g

volume = πr2h = 3.142 * 2 *2 *12 = 150.8cm3

density = 490/150.8 = 3.25g/cm3

porosity = \frac{wet mass - dry mass }{wet mass} = \frac{0.525 - 0.49}{0.525} = 0.07 or 7%

water content =  \frac{wet mass - dry mass}{wet mass} = 7%

8 0
4 years ago
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Which of the following methods of obtaining digitized images can recognize and preserve text and formatting?
Zarrin [17]
The answer is A a digital camera
6 0
3 years ago
What is a heat engine? State its efficiency (a sketch would be appropriate).
dimulka [17.4K]

Answer:

\eta =\dfrac{Q_1-Q_2}{Q_1}

Explanation:

Heat engine

 Heat engine is a device which produce work while consuming some amount of energy .This engine works in cycle.In other words we can say that Heat engine is a device which covert thermal or chemical energy in to mechanical energy and after that this mechanical energy can be use for producing mechanical work.

Heat engine takes heat from high temperature and rejects heat to lower temperature and producing work.

We know that efficiency given as

\eta =\dfrac{out\ put}{in\ put}

From diagram we can say that

Q_1=Q_2+W

So efficiency

\eta =\dfrac{w}{Q_1}

\eta =\dfrac{Q_1-Q_2}{Q_1}

3 0
3 years ago
A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following
Anvisha [2.4K]

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

 This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

6 0
3 years ago
The manufacturer of a 1.5 V D flashlight battery says that the battery will deliver 9 mA for 40 continuous hours. During that ti
Jet001 [13]

Answer:

a) 144.000 s

b) and c)Battery voltage and power plots in attached image.

   V=-\frac{0.5}{144000} t + 1.5 V[tex]    [tex]P(t)=-(31.25X10^{-9}) t+0.0135  where D:{0<t<40} h

d) 1620 J

Explanation:  

a) The first answer is a rule of three

s=\frac{3600s * 40h}{1h} = 144000s

b) Using the line equation with initial point (0 seconds, 1.5 V)

m=\frac{1-1.5}{144000-0} = \frac{-0.5}{144000}

where m is the slope.

V-V_{1}=m(x-x_{1})

where V is voltage in V, and t is time in seconds

V=m(t-t_{1}) + V_{1} and using P and m.

V=-\frac{0.5}{144000} t + 1.5 V[tex] c) Using the equation VPOWER IS DEFINED AS:[tex] P(t) = v(t) * i(t) [tex]so.[tex] P(t) = 9mA * (-\frac{0.5}{144000} t + 1.5) [tex][tex]P(t) = - (31.25X10^{-9}) t + 0.0135

d) Having a count that.

E = \int\limits^{144000}_{0} {P(t)} \, dt  = \int\limits^{144000}_{0} {v(t)*i(t)} \, dt

E = \int\limits^{144000}_{0} {-\frac{0.5}{144000} t + 1.5*0.009} \, dt = 1620 J

4 0
3 years ago
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