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Law Incorporation [45]
2 years ago
7

In a morphological matrix, which of the following contains the parameters that are essential to a design?

Engineering
1 answer:
choli [55]2 years ago
8 0

In a morphological matrix, the parameters that are essential for a design are in the left column.

<h3>What is a morphological matrix?</h3>

The morphological matrix is ​​a matrix where columns and rows represent the various parameters for solving a problem. The first column is used for the characteristics relevant to the problem; the horizontal lines are filled with possibilities for each of these parameters.

With this information, we can conclude that in a morphological matrix, the parameters that are essential for a project are in the left column.

Learn more about  morphological matrix in brainly.com/question/21120930

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technician a says that dirt bypassing the filter on many common rail injectors can cause an injector to stick open and continuou
NNADVOKAT [17]

Technician a is correct because he says that Many common rail injectors filters can be bypassed by dirt, which can lead to an injector sticking open and continuously fueling a cylinder.

Coalescence is used to separate the water and fuel. To the fuel injector cleaning kit, fasten your air compressor. Diesel engines run at compression ratios that are greater than those of gasoline engines. greater ratio compared to gasoline engines. increased thermal expansion as a result. more fuel energy that is transformed into usable power. The great benefit of using a dry cylinder sleeve is that by quickly installing new sleeves, the cylinder block can be quickly restored to its original specifications. Vacuum drying can be used to get rid of small amounts of water. A nozzle is used to spray the fuel into the vacuum chamber of engines. Air and unsolved free water are taken out of the oil. The fuel is evenly dispersed, which facilitates efficient drying.

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3 0
10 months ago
Identify and describe the three stages of a life cycle analysis.
sesenic [268]
The LCA process is a systematic, phased approach and consists of four components: goal definition and scoping, inventory analysis, impact assessment, and interpretation. The standards are provided by the International Organisation for Standardisation (ISO) in ISO 14040 and 14044, and describe the four main phases of an LCA: Goal and scope definition. Inventory analysis. Impact assessment.

Hope this is helpful
5 0
2 years ago
2. Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performan
oee [108]

The python program is an implementation of the Ackermann function that a system optimizes its performance of recursion.

As per the question,

Here is an implementation of the Ackermann function in Python:

<em />

<em>def ackermann(m, n):</em>

<em>    if m == 0:</em>

<em>        return n + 1</em>

<em>    elif n == 0:</em>

<em>        return ackermann(m - 1, 1)</em>

<em>    else:</em>

<em>        return ackermann(m - 1, ackermann(m, n - 1))</em>

<em />

<em># get input values for m and n from the user</em>

<em>m = int(input("Enter an integer value for m: "))</em>

<em>n = int(input("Enter an integer value for n: "))</em>

<em />

<em># calculate and print the result of the Ackermann function</em>

<em>result = ackermann(m, n)</em>

<em>print("Ackermann ({},{}) = {}".format(m, n, result))</em>

This implementation follows the logic described in the prompt, using a recursive function to calculate the result of the Ackermann function for the given values of m and n.

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<em />

5 0
9 months ago
Technician A says that forma hardened steel may have different strenght áreas. Technician B says that aluminum collapses in a pr
stich3 [128]

Technician B is correct because the way aluminum collapses can be predicted.

Hardened steel and aluminum are two metals used for different purposes including:

  • Construction.
  • Appliances.
  • Small utensils.
  • Airplanes.
  • Vehicles.

These two materials have slightly different features in terms of resistance, flexibility, etc.

In the case of hardened steel, this is considered to be malleable but strong. This means it is possible to change its shape under some conditions but it can resist great forces and pressure. Moreover, if the hardening process is carried out properly all the areas should be equally strong.

On the other hand, aluminum is recognized due to its durability and for being lighter than other materials. Despite this, aluminum is more flexible than steel and collapses under weaker forces. This has been widely studied because aluminum collapse shows a predictable pattern.

Based on this, only technician B is correct.

Learn more in: brainly.com/question/24043240

5 0
2 years ago
A steady flow adiabatic turbine accepts gas at conditions T1, P1 and discharges at conditions T2 and P2. Assuming ideal gas, det
Nimfa-mama [501]

Answer:

W = -3753.8 J

W_{ideal} = - 5163.14 J

W_{lost} = - 1409.34 \ J

S_G = 4.70 \ \ J/K

Explanation:

Given that:

T_1 = 500 \ K \\T_2 = 371 \ K \\T_{\sigma} = 300 \ K\\P_1 = 6 \ bar\\P_2 = 1.2 \ bar\\

\frac{Cp}{R} = \frac{7}{2} \\n = 1

Consider the relation

\frac{Cp}{R} = \frac{7}{2} \\

Cp = \frac{7*R}{2}

Cp = \frac{7*8.314 \ kJ/kmol.K}{2}

Cp = 29.099 \  kJ/kmol.K

Actual work W = ΔH = n Cp (T₂ - T₁)

= 1 × 29.099 (371 - 500)

= -3753.8 J

Change in entropy

ΔS = n[Cp In \frac{T_2}{T_1} - R In \frac{P_2}{P_1}]

ΔS =  1*[29.099 In(\frac{371}{500}) - 8.314 In (\frac{1.2}{6})]

ΔS = 4.6978 J/K

Ideal Work

W_{ideal} = \delta H - T_{\sigma} \delta S

= -3753.8 - 300 ( 4.6978)

= - 5163.14 J

Work lost

W_{lost} = |W_{ideal}-W|

W_{lost} = |-5163.14 -(-3753.8)|

W_{lost} = - 1409.34 \ J

Entropy Generation rate:

S_G = \frac{W_{lost}}{T_{\sigma}}

S_G = \frac{1409.34}{300}

S_G = 4.70 \ \ J/K

5 0
3 years ago
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