Answer:
Answer explained below
Explanation:
The value of here is 9
The value of there is hexadecimal value of DECO here, d = 0x39 aaaa (aaaa is the memory address of here )
We have the object code :-
let's take there address is 0x0007
0x0005 BR there :- 0x120020
0x0007 here: .WORD 9
310003 there: DECO here,d - 0x390007
310005 STOP
.END
Creo haber leído sobre esto..Un “interruptor” yo diría
Answer:
$$\begin{align*}
P(Y-X=m | Y > X) &= \sum_{k} P(Y-X=m, X=k | Y > X) \\ &= \sum_{k} P(Y-X=m | X=k, Y > X) P(X=k | Y > X) \\ &= \sum_{k} P(Y-k=m | Y > k) P(X=k | Y > X).\end{split}$$
Explanation:
\eqalign{
P(Y-X=m\mid Y\gt X)
&=\sum_kP(Y-X=m,X=k\mid Y\gt X)\cr
&=\sum_kP(Y-X=m\mid X=k,Y\gt X)\,P(X=k\mid Y>X)\cr
&=\sum_kP(Y-k=m\mid Y\gt k)\,P(X=k\mid Y\gt X)\cr
}
P(Y-X=m | Y > X) &= \sum_{k} P(Y-X=m, X=k | Y > X) \\ &= \sum_{k} P(Y-X=m | X=k, Y > X) P(X=k | Y > X) \\ &= \sum_{k} P(Y-k=m | Y > k) P(X=k | Y > X).\end{split}$$
Answer:
Explanation:
Attached is the solution to the question
Answer:
q=2313.04
T=690.86°C
Explanation:
Given that
Thickness t= 20 cm
Thermal conductivity of firebrick= 1.6 W/m.K
Thermal conductivity of structural brick= 0.7 W/m.K
Inner temperature of firebrick=980°C
Outer temperature of structural brick =30°C
We know that thermal resistance

These are connect in series

Heat transfer

So heat flux
q=2313.04
Lets temperature between interface is T
Now by equating heat in both bricks

So T=690.86°C