Question

A water jet strikes normal to a fixed plate. If diameter of the outlet of the nozzle is 8 cm,and velocity of water at the outlet is 10 m/s, calculate force required to keep the plate in place.

Answer 1

Answer:

The force required to keep the plate in place is 251.36 N

Explanation:

Force = pressure × area

velocity of water = 10 m/s

height of water = v^2/2g = 10^2/2×9.8 = 5.102 m

pressure = height × rho × g = 5.102 × 1000 × 9.8 = 49999.6 N/m^2

diameter = 8 cm = 8/100 = 0.08 m

area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2

Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N