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devlian [24]
3 years ago
11

A water jet strikes normal to a fixed plate. If diameter of the outlet of the nozzle is 8 cm,and velocity of water at the outlet

is 10 m/s, calculate force required to keep the plate in place.
Engineering
1 answer:
zysi [14]3 years ago
8 0

Answer:

The force required to keep the plate in place is 251.36 N

Explanation:

Force = pressure × area

velocity of water = 10 m/s

height of water = v^2/2g = 10^2/2×9.8 = 5.102 m

pressure = height × rho × g = 5.102 × 1000 × 9.8 = 49999.6 N/m^2

diameter = 8 cm = 8/100 = 0.08 m

area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2

Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N

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3 0
3 years ago
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Which of the following material properties varies with temperature? a)- density b)- viscosity c)- electrical resistance d)- all
Reil [10]

Answer:

(d) all of the above

Explanation:

Effect on the density of temperature: If we increase the temperature of any room then particles of the room moves and to and fro and so density is decrease

Effect on the viscosity  of temperature : viscosity is inversely proportional to the temperature if we increase the temperature viscosity decreases and if we decrease the temperature viscosity increases.

Effect on the resistance of temperature : For metals if we increase the temperature then resistance increases and for semiconductor if we increase the temperature resistance decreases

So from above discussion all the parameter depends on the temperature so option (d( will be the correct option  

6 0
3 years ago
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
AnnZ [28]

Answer:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

Explanation:

The acceleration field is obtained by deriving the components in function of the time. That is to say:

\frac{du}{dt}=2.05\cdot \frac{dx}{dt}+0.656\cdot \frac{dy}{dt}\\\frac{dv}{dt} = -2.18\cdot \frac{dx}{dt} -2.05\cdot \frac{dy}{dt}

Where \frac{dx}{dt} = u and \frac{dy}{dt} = v.

The velocity components at given point are, respectively:

u = 2.424

v=-5.266

Lastly, the acceleration components are found:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

7 0
3 years ago
Rank the magnitudes of the diffusion coefficients from greatest to least for the following systems:(a) Cr in Fe at 600°C; (b) C
jek_recluse [69]

Answer:

Explanation:

The rank of the magnitude of the diffusion coefficient from greatest to least is as follows:

C in Fe at 900°C > Cr in Fe at 900°C > Cr in Fe at 600°C

Reason

C in Fe is an interstitial impurity while Cr in Fe is a substutional impurity.Therefore interstitial impurity occurs in C in Fe systems,while substutitional diffusion occurs in Cr in Fe system.Interstitial is much faster than substitutional diffusion hence the order

Also with increasing temperature magnitude of diffusion coefficient increases,due to the relation.

     D = D₀exp(-Qd/RT)

Where D₀=Temperature independent per exponential

           Qd= The activation energy for diffusion

             R= Universal gas constant

              T=absolute temperature

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