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devlian [24]
3 years ago
11

A water jet strikes normal to a fixed plate. If diameter of the outlet of the nozzle is 8 cm,and velocity of water at the outlet

is 10 m/s, calculate force required to keep the plate in place.
Engineering
1 answer:
zysi [14]3 years ago
8 0

Answer:

The force required to keep the plate in place is 251.36 N

Explanation:

Force = pressure × area

velocity of water = 10 m/s

height of water = v^2/2g = 10^2/2×9.8 = 5.102 m

pressure = height × rho × g = 5.102 × 1000 × 9.8 = 49999.6 N/m^2

diameter = 8 cm = 8/100 = 0.08 m

area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2

Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N

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An operating gear box (transmission) has 350 hp at its input shaft while 250. hp are delivered to the output shaft. The gear box
True [87]

Answer:

Rate of Entropy =210.14 J/K-s

Explanation:

given data:

power delivered to input = 350 hp

power delivered to output = 250 hp

temperature of surface = 180°F

rate of entropy is given as

Rate\  of\ entropy  = \frac{Rate\ of \ heat\  released}{Temperature}

T = 180°F = 82°C = 355 K

Rate of heat = (350 - 250) hp = 100 hp = 74600 W

Rate of Entropy= \frac{74600}{355} = 210.14 J/K-s

8 0
3 years ago
A tank with some water in it begins to drain. The function v ( t ) = 46 − 3.5 t determines the volume of the water in the tank (
olchik [2.2K]

Answer with Explanation:

Part a)

The volume of water in the tank as a function of time is plotted in the below attached figure.

The vertical intercept of the graph is 46.

Part b)

The vertical intercept represents the volume of water that is initially present in the tank before draining begins.

Part c)

To find the time required to completely drain the tank we calculate the volume of the water in the tank to zero.

0=46-3.5t\\\\3.5=46\\\\\therefore t=\frac{46}{3.5}=13.143minutes

Part d)

The horizontal intercept represents the time it takes to empty the tank which as calculated above is 13.143 minutes.

7 0
3 years ago
50POINTS
maxonik [38]

Answer:

Ensure that all material and energy inputs and outputs are as inherently safe and benign as possible. Minimize the depletion of natural resources. Prevent waste. Develop and apply engineering solutions while being cognizant of local geography, aspirations, and cultures.Green engineering is the design, commercialization, and use of processes and products that minimize pollution, promote sustainability, and protect human health without sacrificing economic viability and efficiency.The goal of environmental engineering is to ensure that societal development and the use of water, land and air resources are sustainable. This goal is achieved by managing these resources so that environmental pollution and degradation is minimized.

Explanation:i helped

7 0
3 years ago
Read 2 more answers
Can someone pls give me the answer to this?
Zolol [24]
During World War ll, the United States and the Soviet Union fought together as the allies against the Axis power. However, the relationship between the two nations was a tense one. Americans had long been wary of Soviet communism and concerned about Russian leader Joseph Stalin’s tyrannical rule of his own country
7 0
3 years ago
An asbestos pad is square in cross section, measuring 5 cm on a side at its small end increasing linearly to 10 cm on a side at
polet [3.4K]

Answer:

q = 1.73 W

Explanation:

given data

small end  = 5 cm

large end = 10 cm

high = 15 cm

small end is held = 600 K

large end at = 300 K

thermal conductivity of asbestos  = 0.173 W/mK

solution

first we will get here side of cross section that is express as

S = S1 + \frac{S2-S1}{L} x     ...............1

here x is distance from small end and S1 is side of square at small end

and S2 is side of square of large end and L is length

put here value and we get

S = 5 + \frac{10-5}{15} x

S = \frac{0.15 + x}{3}    m

and  

now we get here Area of section at distance x is

area A = S²    ...............2

area A = (\frac{0.15 + x}{3})^2    m²

and

now we take here small length dx and temperature difference is dt

so as per fourier law

heat conduction is express as

heat conduction q = \frac{-k\times A\  dt}{dx}      ...............3

put here value and we get

heat conduction q = -k\times (\frac{0.15 + x}{3})^2 \   \frac{dt}{dx}  

it will be express as

q \times \frac{dx}{(\frac{0.15 + x}{3})^2} = -k (dt)  

now we intergrate it with limit 0 to 0.15 and take temp 600 to 300 K

q \int\limits^{0.15}_0 {\frac{dx}{(\frac{0.15 + x}{3})^2 } = -0.173 \int\limits^{300}_{600} {dt}          

solve it and we get

q (30)  = (0.173) × (600 - 300)

q = 1.73 W

5 0
3 years ago
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