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puteri [66]
3 years ago
6

In a fluid power system, if energy is not transferred to work, what form does it take?

Engineering
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

I think its heat but im not sure

Explanation:

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The four strokes in a four stroke cycle engine in proper order.
Morgarella [4.7K]

Answer:

A four-stroke cycle engine is an internal combustion engine that utilizes four distinct piston strokes (intake, compression, power, and exhaust) to complete one operating cycle. The piston make two complete passes in the cylinder to complete one operating cycle.

Explanation:

6 0
3 years ago
What is 39483048^349374*3948048/3i4u4
Verizon [17]

Answer:

1.  3.81813506×10^2^9

2.  1.71479428×10^6^5

3.  9.38483383×10^2^6

4.  1.150847×10^2^9

Explanation:

Feel free to give brainliest

Have a great day!

3 0
2 years ago
Any help is appreciated <3
Len [333]

Answer:

forwarder

Explanation:

8 0
3 years ago
When an object is moving, we use the following coefficient for friction calculations a)-μk b)-μs c)-γk d)- γs
Reika [66]

Answer:\mu_{k}

Explanation:

We use kinetic friction when a body is moving i.e. \mu_{k} for calculations.

Static friction is used when a body is in rest while kinetic friction is used when a body is moving and its value is quite low as compared to static friction .

Static friction value increases as we apply more force while kinetic friction occurs when there is relative motion between bodies.

3 0
3 years ago
An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through th
sp2606 [1]

Answer:

<em> - 14.943 W/m^2K  ( negative sign indicates cooling ) </em>

Explanation:

Given data:

Area of FPC = 4 m^2

temp of water = 60°C

flow rate = 0.06 l/s

ambient temperature = 8°C

exit temperature = 49°C

<u>Calculate the overall heat loss coefficient </u>

Note : heat lost by water = heat loss through convection

m*Cp*dT  = h*A * ( T - To )

∴ dT / T - To = h*A / m*Cp  ( integrate the relation )

In ( \frac{49-8}{60-8} ) =  h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )

In ( 41 / 52 ) = 0.0159*h

hence h = - 0.2376 / 0.0159

              = - 14.943  W/m^2K  ( heat loss coefficient )

7 0
2 years ago
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