In the front side of the submarines and torpedoes, the small area of contact is maintained to reduce the pressure or the drag force on the submarines due to the water.
The drag force in terms of the area of cross-section of the submarine is,
where F_d is the drag force acting on the submarine and A is the area of cross-section of a submarine in contact with the water,
There is also piped formation that takes place through which the water runs lengthwise while the submarine is moving in the forward direction, thus, reduces the force on the submarine due to the water.
Answer:
20,850 N
Explanation:
We can solve the problem by using second Newton's Law:
where
F is the force
m is the mass
a is the acceleration
In this problem, we have:
m = 70 kg is the mass
is the acceleration (which is negative, because it is a deceleration)
So, we can use the equation above to find the force:
and the negative sign simply means that the force is in the opposite direction to the motion.
