3 years ago

A 1700kg rhino charges at a speed of 50.0km/h. what average force is needed to bring the rhino to a stop in 0.50s?

1 answer:

6 0

From 50km/h to 0km/h in 0.5s we need next acceleration:
First we convert km/h in m/s:
50km/h = 50*1000/3600=13.8888 m/s
a = v/t = 13.88888/0.5 = 27.77777 m/s^2

Now we use Newton's law:

F=m*a

F=1700*27.7777 = 47222N

You might be interested in

What is the critical angle for light traveling from crown glass (n = 1.52) into water (n = 1.33)?

Flauer [41]

Answer:

61 degrees, I just did the test.

Explanation:

6 0

3 years ago

Read 2 more answers

A force of 70 N is applied to a 28 kg rock causing it to slow down from 25 m/s to 15 m/s, a change in velocity of 10 m/s. How lo

maksim [4K]

Answer: 4 s

Explanation:

Given

The applied force is 70 N

mass of the rock is 28 kg

initial velocity $u=25\ m/s$

final velocity $v=15\ m/s$

Deceleration provided by force is

$a=-\dfrac{70}{28}=-2.5\ m/s^2$

using the equation of motion

$v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s$

7 0

3 years ago

Some areas of the Earth receive more solar radiation than others. Which of the following results from the Sun's uneven heating o

GuDViN [60]

The core of the earth lets out radiation from under the ground which make the core responce of how volcano's errupt.

7 0

3 years ago

What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?

lora16 [44]

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

$v = H_o D\\\\H_o = \frac{v}{D}$

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

$H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}$

3 0

2 years ago

A 20 kg object is floating in space. What is its mass?

trapecia [35]

It's still 20 kg. Mass doesn't change according to gravity, only weight changes.

5 0

3 years ago