Answer:1)1.99 M
Explanation:
Molarity is given as = moles solute/Liter solution
The solute which is LiOH is already given in moles as 1.495 moles
Given that solution is 750 mL, we convert to liters.
Liters of the solution= mL of the solution x (1 L/1000 mL)
750 mL x (1 L/1000 mL)
0.75 L
Molarity = moles solute/Liter solution
Molarity = 1.495 moles of LiOH/0.75 L of solution
Molarity = 1.99M
The molarity of this solution is 1.99M (moles per liter).
A is incorrect because, the carbon dioxide is being pushed up by the below mixture of baking soda and vinegar.
B is incorrect because the carbon dioxide gets pushed out of the bottle and joins the air around the bottle, adding carbon dioxide to the air around the bottle.
C is incorrect because the mass of the reactants, the baking soda and vinegar, is more then the carbon dioxide it creates.
D is correct because the mass of the reactants is more then the carbon dioxide it creates.
I hope this helps you. please mark brainliest, thank you :)
The answer should be (3) <span>They have different molecular structures and different properties.
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Answer:
0.6 Molar
Explanation:
According to the Question,
In 500 mL of water ,
0.2 mol sample of MgCl is present and 0.1 mol of KCl is present.
Thus ,
Concentration of Cl anion in the solution will be the sum of Cl anion concentration from MgCl and KCl.
From MgCl , 0.2 mol of Cl anion will come and 0.1 mol of KCl anion will come ,
Thus , 0.3 mol of Cl anion will come totally .
So, Cl anion concentration will be = 0.6 M
Answer:
34.8 g
Explanation:
Answer:
We have the masses of two reactants, so this is a limiting reactant problem.
We will need a balanced equation with masses, moles, and molar masses of the compounds involved.
1. Gather all the information in one place with molar masses above the formulas and masses below them.
Mᵣ: 123.90 70.91 208.24
P₄ + 20Cl₂ ⟶ 4PCl₅
Mass/g: 46.0 32.0
2. Calculate the moles of each reactant
3. Calculate the moles of PCl₅ we can obtain from each reactant
From P₄:
The molar ratio is 4 mol PCl₅:4 mol P₄
From Cl₂:
The molar ratio is 4 mol PCl₅:20 mol Cl₂
4. Identify the limiting and excess reactants
The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.
The excess reactant is phosphorus.
5. Mass of excess reactant
(a) Moles of P₄ reacted
The molar ratio is 1 mol P₄:20 mol Cl₂
(b) Mass of P₄ reacted
(c) Mass of P₄ remaining
Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄