Dissociation reaction of calcium hydroxide can be represented as follows:
<span>Ca(OH)2 (s) ⇄ Ca2+(aq) + 2OH-(aq)
</span>
The solubility product of Ca(OH)2 is mathematically expressed as
Ksp = [Ca2+] [OH-]^2
Given: Ksp = <span>4.68 x 10-6
Now, we know that for aqueous system, pH + pOH = 14
and pOH = -log(OH-)
Thus, [OH-] = </span><span>10^(pH - 14)
</span>∴ Ksp = [Ca2+] [10^(pH - 14)]^2 = [Ca2+] [10^(2.pH - 28)]
∴ [Ca2+] = Ksp/10^(2.pH - 28)
= Ksp 10^(28 - 2.pH)
Now, at pH = 4
[Ca2+] = Ksp 10^(28 - 2.pH)
= (4.68 x 10-6) 10^(28 - 2X4)
= 4.68 X 10^14 mol/dm3
At pH = 7,
[Ca2+] = Ksp 10^(28 - 2.pH)
= (4.68 x 10-6) 10^(28 - 2X7)
= 4.68 X 10^8 mol/dm3
At pH = 9
[Ca2+] = Ksp 10^(28 - 2.pH)
= (4.68 x 10-6) 10^(28 - 2X9)
= 4.68 X 10^4 mol/dm3
Answer:
Following is molar solubility of calcium hydroxide at different pH
at pH 4 = 4.68 X 10^14 mol/dm3
at pH 7 = 4.68 X 10^8 mol/dm3
at pH 9 = 4.68 X 10^4 mol/dm3
<h3>Changes with the independent variable...</h3>
Can’t help you man, sorry
Even though an atom may be smaller than another atom, it might have more mass. The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the object divided by its volume; D = m/v. Objects with the same mass but different volume have different densities.
Answer:
A A B
Explanation:
I know that when it is slopped it is 90% always accelerating
