Answer:
Oxygen is the most contain in earth but you asked in a,b,c and d. So I'll choice A. aluminium.
6,02×10²³ * 3,2 = 19,264×10²³=1,9264×10²⁴
Answer:
205.12 atm
Explanation:
Using the ideal gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
R = 0.0821 Latm/perK)
T = temperature (K)
n = number of moles (mol)
According to the information in this question;
P = ?
V = 34.25 mL = 34.25 ÷ 1000 = 0.03425L
n = 0.215 mol
T = 125.0°C = 125 + 273 = 398K
Using PV = nRT
P = nRT ÷ V
P = (0.215 × 0.0821 × 398) ÷ (0.03425)
P = 7.025 ÷ 0.03425
P = 205.12 atm
Answer:
297 J
Explanation:
The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of 1 g of a given substance by 1∘C.
In your case, aluminium is said to have a specific heat of 0.90Jg∘C.
So, what does that tell you?
In order to increase the temperature of 1 g of aluminium by 1∘C, you need to provide it with 0.90 J of heat.
But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by 1∘C. So if you wanted to increase the temperature of 10.0 g of aluminium by 1∘C, you'd have to provide it with
1 gram0.90 J+1 gram0.90 J+ ... +1 gram0.90 J10 times=10×0.90 J
However, you don't want to increase the temperature of the sample by 1∘C, you want to increase it by
ΔT=55∘C−22∘C=33∘C
This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that
1∘C10×0.90 J+1∘C10×0.90 J+ ... +
answer: elements are on the periodic table
