To determine the standard heat of reaction, ΔHrxn°, let's apply the Hess' Law.
ΔHrxn° = ∑(ν×ΔHf° of products) - ∑(ν×ΔHf° of reactants)
where
ν si the stoichiometric coefficient of the substances in the reaction
ΔHf° is the standard heat of formation
The ΔHf° for the substances are the following:
CH₃OH(l) = -238.4 kJ/mol
CH₄(g) = -74.7 kJ/mol
O₂(g) = 0 kJ/mol
ΔHrxn° = (1 mol×-74.7 kJ/mol) - ∑(1 mol×-238.4 kJ/mol)
ΔHrxn° = +163.7 kJ
Answer:
BaO
Explanation:
The barium oxide chemical formula is BaO. The molar mass is 153.33 g/mol. The molecule is formed by one barium cation Ba2+ and one oxide anion O2-. Both ions are bound by one ionic bond.
Answer:
Alpha is when you are the leader of the pack. Beta is the weaker but can become alpha by killing th ealpha.
Explanation:
the double helix is hydrogen bonded through the bases only so the bases are inside the helix only
as adenine combines with thymine and guanine with cytosine
phosphate are in the exterior of it
sugar groups constitute the double helix.