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RUDIKE [14]
3 years ago
12

Describe the possible components of a buffer solution. (select all that apply.)strong base and its conjugate acidweak base and i

ts conjugate acid
Chemistry
1 answer:
Viktor [21]3 years ago
6 0
Missing question:

a) strong base and its conjugate acid.

b) weak base and its conjugate acid.

c) strong acid and strong base.

d) weak acid and its conjugate base.

e) weak acid only.

f) weak base only.

g) strong acid and its conjugate base.

Answers are: 

b) weak base and its conjugate acid. For example weak base ammonia (NH₃) and its conjugate acid ammonium ion (NH₄⁺).

d) weak acid and its conjugate base. For example weak acetic acid (CH₃COOH) and its conjugate base CH₃COO⁻.

Buffer solution changes pH very little when a small amount of strong acid or base<span> is added to solution.</span>


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A stock solution of HNO3 is prepared and found to contain 13.5 M of HNO3. If 25.0 mL of the stock solution is diluted to a final
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Answer : The correct option is, (C) 0.675 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = concentration of HNO_3 = 13.5 M

M_2 = concentration of diluted solution = ?

V_1 = volume of HNO_3 = 25.0 ml  = 0.0250 L

conversion used : (1 L = 1000 mL)

V_2 = volume of diluted solution = 0.500 L

Now put all the given values in the above law, we get the concentration of the diluted solution.

13.5M\times 0.0250L=M_2\times 0.500L

M_2=0.675M

Therefore, the concentration of the diluted solution is 0.675 M

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2 years ago
Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?
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<span>Answer: K because it is metal and typically forms ionic bonds. Ar is also unlikely to form any bonds because it has a full outer shell of electrons, but it can form covalent bonds.</span>
4 0
3 years ago
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A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium ha
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When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:

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when 
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Cw → specific heat of water
ΔTw → difference in temperature for water 

Mm→ mass of metal
Cw→ specific heat of the metal
ΔTm → difference in temperature for metal

by substitution:

100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)

∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C

when the Cm of the Magnesium ∴ the unknown metal is Mg
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Can anything change solutions? Be<br> specific!
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What kind of solutions?
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