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timama [110]
3 years ago
15

Solve for a, b, c, AND d d C 84° 930 970 b

Chemistry
2 answers:
VARVARA [1.3K]3 years ago
8 0
A is 87
B is 83
C is 96
D is 94
You can simply subtract the given degree from 180
And for D you should subtract the sum of given degree from 360 and do as above
olga55 [171]3 years ago
5 0

Answer:

a = 87

b = 83

c = 96

d = 86

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element m is a metal and its chloride has the formula mcl2. to which group of the periodic table does m most likely belong
Triss [41]
It will belong to the metals because metals bond with nonmetals like chlorine to form ionic compounds
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NEED HELP!<br> Please refer to the picture for the question!
Mashutka [201]

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Check all items common to bases.<br> minerals<br> metal<br> gas<br> H+<br> OH-<br> nitrogen
Darya [45]

OH- is common to bases.

Explanation:

The base is a is an ionic compounds which when placed in aqueous solution dissociates in to a cation and an anion OH-.

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8 0
3 years ago
How many grams of sodium chloride are required to make a 1.0 L solution with a concentration of 3.5 M?
satela [25.4K]
3.5 M has 3.5 moles per litre
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5 0
3 years ago
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Under certain conditions, the equilibrium constant of the reaction below is Kc=1.7×10−3. If the reaction begins with a concentra
svetoff [14.1K]

Answer:

[Cl2] equilibrium = 0.0089 M

Explanation:

<u>Given:</u>

[SbCl5] = 0 M

[SbCl3] = [Cl2] = 0.0546 M

Kc = 1.7*10^-3

<u>To determine:</u>

The equilibrium concentration of Cl2

<u>Calculation:</u>

Set-up an ICE table for the given reaction:

               SbCl5(g)\rightleftharpoons SbCl3(g)+Cl2(g)

I                 0                    0.0546     0.0546

C              +x                        -x               -x

E               x                  (0.0546-x)    (0.0546-x)

Kc = \frac{[SbCl3][Cl2]}{[SbCl5]}\\\\1.7*10^{-3} =\frac{(0.0546-x)^{2} }{x} \\\\x = 0.0457 M

The equilibrium concentration of Cl2 is:

= 0.0546-x = 0.0546-0.0457 = 0.0089 M

5 0
3 years ago
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