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Andre45 [30]
1 year ago
13

what is the wavelength of light (in nanometers) that has a frequency of 1.75 x 1013 hz? the speed of light is 3.00 x 108 m/s.

Physics
1 answer:
Leokris [45]1 year ago
5 0

The light has a frequency of 1.75 x 10¹³ hz. The speed of light is 3.00 x 10⁸ m/s. The wavelength of light is (λ) = 1.714 x 10⁴ nm

<h3>What is wavelength?</h3>

When a wave that propagates in a medium it has different lengths. That length of the wave is called the wavelength. It can be measured in m, cm, nm etc.

<h3>How can we calculate the wavelength?</h3>

To calculate the wavelength we are using the formula,

λ=c/f

Here we are given,

c= The speed of light in zero space. = 3.00 x 10⁸ m/s.

f = The frequency of the light. = 1.75 x 10¹³ hz.

We have to calculate the wavelength of the light = λ m

Now we put the values in above equation we get,

λ=c/f

Or, λ=3.00 x 10⁸ / 1.75 x 10¹³

Or,  λ= 1.714 x 10⁻⁵ m

So we can easily say that,

The wavelength of light is (λ) =1.714 x 10⁻⁵ m = 1.714 x 10⁴ nm

Learn more about wavelength:

brainly.com/question/10728818

#SPJ4

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Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume
Mamont248 [21]

Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 490 km

a = Acceleration

g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

3 0
4 years ago
Read 2 more answers
A tank contains 150 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
nikitadnepr [17]

Answer:

The number A(t) of grams of salt in the tank at time t is A(t) = 150 - 110 e^{-\frac{t}{50} }

Explanation:

Knowing

\frac{dA}{dt} = Rin - Rout

First we have to find the Rin and Rout

Rin = (concentration of the salt inflow) * (input rate of brine)

Rin = 1 g/L * 3 L/min = 3 g/L

Rout = (concentration of the salt outflow) * (output rate of brine)

Rout = (\frac{A(t)}{150} g/L) * (3 L/min) = \frac{A(t)}{50} g/min

Substituting this results

\frac{dA}{dt} = 3 - \frac{A(t)}{50} --> \frac{dA}{dt} + \frac{1}{50} A(t)  = 4

Thus, integration factors is

e^{ \int\limits^._. {\frac{1}{50} } \, dt } = e^{\frac{t}{50} }

e^{\frac{t}{50} } \frac{dA}{dt} + \frac{1}{50} e^{\frac{t}{50} A(t) = 4 e^{\frac{t}{50} }

e^{\frac{t}{50} } A(t) = \int\limits^._. {3 e^{\frac{t}{50} } } \, dt\\ \\A(t) = 150 + c e^{-\frac{t}{50} }

Applying the initial conditions

A(0) = 40

c = 150 - 40 = 110

Now, substitute this result in the solution to get

A(t) = 150 - 110 e^{-\frac{t}{50} }

8 0
4 years ago
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