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marissa [1.9K]
3 years ago
7

A string vibrates at a frequency of 20Hz. what is its period?

Physics
1 answer:
Andreas93 [3]3 years ago
7 0
We know, Period = 1/frequency = 1/20 sec.

So, your final answer is 0.05 sec

Hope this helps!
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A mosquito flying over a highway strikes a windshield of a moving truck. Compared to the magnitude of the force of the truck on
krok68 [10]

Answer:

the answer to this question is

<em>The</em><em> </em><em>Same</em><em> </em>

<em>newton's</em><em> </em><em>law</em><em> </em><em>#3</em>

Explanation:

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em>

3 0
3 years ago
A block of mass 3.6 kg, sliding on a horizontal plane, is released with a velocity of 1.7 m/s. The block slides and stops at a d
pentagon [3]

Answer:

The block would have slid <u>12.6 m</u> if its initial velocity were increased by a factor of 2.8.

Explanation:

Given:

Mass of the block (m) = 3.6 kg

Initial velocity (u) = 1.7 m/s

Final velocity (v) = 0 m/s

Displacement (S) = 1.6 m

First we will find the acceleration of the block.

Using the equation of motion, we have:

v^2=u^2+2aS\\\\a=\dfrac{v^2-u^2}{2S}

Now, plug in the given values and solve for 'a'. This gives,

a=\frac{0-1.7^2}{2\times 1.6}\\\\a=\frac{-2.89}{3.2}=0.903\ m/s^2

The acceleration is negative as it is resisting the motion.

Now, the initial velocity is increased by a factor of 2.8. So,

New initial velocity = 2.8 × 1.7 = 4.76 m/s

Again using the same equation of motion and expressing the result in terms of 'S'. This gives,

v^2=u^2+2aS\\\\S=\dfrac{v^2-u^2}{2a}

Now, plug in the given values and solve for 'S'. This gives,

S=\frac{0-4.76^2}{2\times -0.903}\\\\S=\frac{-22.6576}{-1.806}=12.6\ m

Therefore, the block would have slid 12.6 m if its initial velocity were increased by a factor of 2.8

6 0
3 years ago
With good tires and breaks, a car traveling 50 mi/hr on dry pavement can travel 400 ft when the driver reacts to something he se
Bogdan [553]

Answer:6.72 m/s^2

Explanation:

Given

initial velocity u=50 mi/hr\approx 73.33 ft/s

Distance traveled before stopping s=400 ft

using equation of

v^2-u^2=2as

where v=final velocity

u=initial Velocity

a=acceleration

s=displacement

v=0 as car stops after travelling 400 ft

0-73.33^2=2\times a\times 400

a=-6.72 m/s^2

negative sign indicates it is deceleration

3 0
3 years ago
The force of gravity is also known as
kolbaska11 [484]

Answer:

Gravitation

Explanation:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.

8 0
3 years ago
Do you remove the positive or negative first on a car battery?
nevsk [136]

Answer:

negative at first.

Explanation:

It's important to disconnect the negative side at first, otherwise you can cause an electrical short if positive is removed first.

4 0
1 year ago
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