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marissa [1.9K]
3 years ago
7

A string vibrates at a frequency of 20Hz. what is its period?

Physics
1 answer:
Andreas93 [3]3 years ago
7 0
We know, Period = 1/frequency = 1/20 sec.

So, your final answer is 0.05 sec

Hope this helps!
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Activation Energy is the amount of energy needed to get a reaction started.
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Why are there no hurricanes in Alaska?
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An 805-kg race car can drive around an unbanked turn at a maximum speed of 54 m/s without slipping. the turn has a radius of cur
SIZIF [17.4K]
(a) Equating centripetal force to friction force, one finds the relation
  v² = kar
for car speed v, coefficient of friction k, radius of curvature r, and downward acceleration a.

There is already downward acceleration due to gravity. The additional accceleration due to the wing is
  a = F/m = 10600 N/(805 kg) ≈ 13.1677 m/s²
We presume this is added to the 9.80 m/s² gravity provides, so the coefficient of friction is
  k = v²/(ar) = (54 m/s)²/((13.1677 m/s² +9.80 m/s²)·(155 m))
  k ≈ 0.8191

(b) The maximum speed is proportional to the square root of the downward acceleration. Changing that by a factor of 9.80/(9.80+13.17) changes the maximum speed by the square root of this factor.
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8 0
3 years ago
Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga
Yakvenalex [24]

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\

you do "a" the subject of the equation and replace the values of the other parameters:

a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}

next, the force, by using the second Newton law is:

F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N

hence, the force is 592238.09 N

- - - - - - - - - - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

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That's all I got, sorry
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