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noname [10]
1 year ago
13

Three diagrams shown here represent solutions and one does not. Which two diagrams represent solutions in which the solutes are

nonelectrolytes

Chemistry
1 answer:
Kamila [148]1 year ago
7 0

Chemistry => Solution =>Solution

A solution is defined as a homogeneous mixture of two or more dissolved substances, that is, when mixing two substances there will be only one visible phase.

The first figure is not a solution since it is observed that the molecules are precipitated at the bottom, so they will be as solid particles.

Therefore, we will have to:

Electrolytes are characterized by the fact that they separate into ions in solution.

Circled images represent solutions with no electrolytes.

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Identify all the examples that support the Law of Conservation of Mass through chemical changes.
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Answer:

B

C

Explanation:

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What is the energy of light with a wavelength of 589 nm? (The speed of light in a vacuum is 3.00 x 10^8 m/s, and Planck's consta
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B

Explanation:

\frac{6.626\cdot10^{-34}\cdot\left(3\cdot10^{8}\right)}{589}= 3.37 x 10^-28 J

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3 years ago
Count the atoms in this common formula for the explosive TNT<br><br> 2C7H5(NO2)3
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Explanation:

7 carbon atoms, 6 hydrogen atoms,9 NO2 atoms

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CaCO3(s) ∆→CaO(s) + CO2(g).
sveta [45]

Answer:

74.9%.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Ca: 40.078;
  • C: 12.011;
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What's the <em>theoretical</em> yield of this reaction?

In other words, what's the mass of the CO₂ that should come out of heating 40.1 grams of CaCO₃?

Molar mass of CaCO₃:

M(\text{CaCO}_3) = 40.078 + 12.011 + 3 \times 15.999 = 100.086\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of CaCO₃ available:

\displaystyle n(\text{CaCO}_3) =\frac{m}{M} = \frac{40.1}{100.086} = 0.400655\;\text{mol}.

Look at the chemical equation. The coefficient in front of both CaCO₃ and CO₂ is one. Decomposing every mole of CaCO₃ should produce one mole of CO₂.

n(\text{CO}2) = n(\text{CaCO}_3)= 0.400655\;\text{mol}.

Molar mass of CO₂:

M(\text{CO}_2) = 12.011 + 2\times 15.999 = 44.009\;\text{g}\cdot\text{mol}^{-1}.

Mass of the 0.400655 moles of \text{CO}_2 expected for the 40.1 grams of CaCO₃:

m(\text{CO}_2) = n\cdot M = 0.400655 \times 44.009 = 17.632\;\text{g}.

What's the <em>percentage</em> yield of this reaction?

\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%.

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Which one of the following would you expect to dissolve in water? limonene sucrose oil atmospheric oxygen none of the above
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-----------sucrose----------------

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