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Ugo [173]
3 years ago
8

Identify all the examples that support the Law of Conservation of Mass through chemical changes.

Chemistry
2 answers:
wariber [46]3 years ago
7 0

Answer:

B

C

Explanation:

slega [8]3 years ago
5 0
I think it’s b and c
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Craig needs to organize, analyze, and interpret large amounts of quantitative data that he generated during an experiment. Which
notsponge [240]

Answer:

C. a computer

Explanation:

Quantitative data are measures of values or counts and are expressed as numbers. The best tool out of all shown to deal with a large amount of numerical data is a computer

4 0
3 years ago
Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,
WITCHER [35]

Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

6 0
3 years ago
The Law of _____states that substances combine in predictable proportions and that excess reactants remain unchanged.
RideAnS [48]

Answer: definite proportions.


Explanation:


1) The definite proportions law states that compounds will always have the same kind of atoms (elements) in the same mass proportion (ratios).


2) For example, a molecule of water will alwys have the same mass ratio of hydrogen atoms to oxygen atoms. That is what permits to obtain the chemical formula of the water molecule as H₂O.


The mass of the two hydrogen atoms will be in a fixed ratio respect to the mass of the oxygen atoms.


Then, if you have one reactant in less proportion than the other, respect to the ratio stated by the chemical formula of water, the former will react completely (it is the limiting reactant) with the corresponding (proportional) mass of the later. Then there will be an excess of the later reactant which will not react (will remain unchanged).


The reactants can only react in the proportion defined by the chemical formulas of the final products.

4 0
3 years ago
Read 2 more answers
A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
Katen [24]

Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K  

8 0
3 years ago
Which sediment type requires the least amount of energy to be eroded
castortr0y [4]

Answer:

SEDIMENTARY ROCK

Explanation:

8 0
3 years ago
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