Answer: A.) Look at the benefits and challenges of using specific materials.
Explanation: They can’t decide whether they made the best product or not because it is a new project.
<u>Answer:</u> The balanced chemical equation is written below.
<u>Explanation:</u>
Double displacement reaction is defined as the reaction in which exchange of ions takes place.

When sodium permanganate reacts with iron (III) chloride, it leads to the production of sodium chloride and iron (III) permanganate.
The chemical equation for the reaction of sodium permanganate and iron (III) chloride follows:

By Stoichiometry of the reaction:
3 moles of aqueous solution of sodium permanganate reacts with 1 mole of aqueous solution of iron (III) chloride to produce 1 mole of solid iron permanganate and 3 moles of aqueous solution of sodium chloride
Hence, the balanced chemical equation is written above.
The volume of the unit cell is 2.67 x 10⁻²⁸ m³.
<h3>What is the volume of a unit cell of a body-centered cubic crystal?</h3>
In a body-centered cubic unit cell, the volume occupied by the particles of the substance is about 68% of the total unit cell.
Assuming that a single atomic a sphere, the volume is:
Volume(atom) = 4/3 x π x r³
Volume(atom) = 4/3 x π x (169 x 10⁻¹²)³
Volume(atom) = 2.02 x 10⁻²⁹ m³
There are a total of 9 atoms in a body-centered unit cell, so the total volume occupied by atoms is:
2.02 x 10⁻²⁹ x 9
= 1.82 x 10⁻²⁸ m³
Volume of cell = (1.15 x 10⁻²⁸ ) / 0.68
Volume of cell = 2.67 x 10⁻²⁸ m³
Therefore, the volume of the unit cell is 2.67 x 10⁻²⁸ m³.
Learn more volume of unit cells at: brainly.com/question/1594030
#SPJ1
Answer:
V = 22.34 L
Explanation:
Given data:
Volume of O₂ needed = ?
Temperature and pressure = standard
Number of molecules of water produced = 6.0× 10²³
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of water:
1 mole contain 6.022× 10²³ molecules
6.0× 10²³ molecules × 1 mole / 6.022× 10²³ molecules
0.99 mole
Now we will compare the moles of oxygen and water.
H₂O : O₂
2 : 1
0.996 : 0.996
Volume of oxygen needed:
PV = nRT
V = nRT/P
V = 0.996 mol × 0.0821 atm.L/mol.K × 273.15 K / 1 atm
V = 22.34 L