B. 6 atoms of carbon C
I would think this is the answer, because one can't just delete or add atoms; otherwise, the equation would be unbalanced. This also abides with the Law of Conservation of Mass.
Plus, I also came to that conclusion because if we look at the net equation of photosynthesis:
––>
The number of Carbon atoms is 6 on both the reagent's side and the product's side.
Daughter cells?
It might be called haploid daughter cells too.
<u>Answer:</u>
<em> needed to heat the amount of water giving.
</em>
<u>Explanation:</u>
To solve this question we first need to know the specific heat of water which is given by <em>4.18 joules</em> Per gram for increasing <em>1° of temperature</em>. Now since one gram of water name one joules per gram so 2 grams will need <em>twice of 4.18</em> that is 8.36 similarly 50 grams will need
Now we need to calculate the heat for 10° of change because temperature rises from 50° centigrade to 60° centigrade and difference in degrees
<em>so heat needed is= </em>
Answer: -
First Ionization energy IE 1 for element X = 801
Here X is told to be in the third period.
So principal quantum number n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom. Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
<u>Answer:</u> The mass percent of silicon in the given compound is 15.9 %
<u>Explanation:</u>
We are given:
A chemical compound having chemical formula
To calculate the percent by mass of silicon in given compound, we use the equation:
Mass of silicon =
Mass of compound =
Putting values in above equation, we get:
Hence, the mass percent of silicon in the given compound is 15.9 %