Answer: 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal
Explanation:
To calculate the moles :
The balanced chemical equuation is:
According to stoichiometry :
4 moles of 
produce == 2 moles of 
Thus 0.556 moles of will produce=
of
Mass of 
Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.
Hello!
I believe the answer is A) Anaphase.
I hope it helps!
Answer:
The answer to your question is: letter B
Explanation:
Reaction
Cr2O3(s) + 3CCl4(l) ⇒ 2CrCl3(s) + 3COCl2(g)
From the information given and the reaction, we can conclude that:
Green solid = Cr2O3 (s) "s" means solid
Colorless liquid = CCl4 (l) "l" means liquid and is the other reactant
Purple solid = CrCl3(s) CrCl3 is purple and "s" solid
Then, as a green specks remains it means that the excess reactant is Cr2O3, so, CCl4 is the limiting reactant.
The mass of stars affect how they end.
Stars with greater mass sometimes end with supernovas, a giant explosion, which can result in black holes or neutron stars, or sometimes nothing.
A medium sized star can result in a planetary nebula, which then results in a white dwarf.
Haha hope this sorta helped :)
There are several information's already given in the question. Based on those information's the answer can be easily determined.
M = <span>1.11 g CH4
C = </span>4.319 kJ g C⋅°
∆T = 35.65 - 24.85 degree centigrade
= 10.8 degree centigrade.
Then
∆H =−M ⋅ C ⋅∆T
= - 1.11 * 4.319 * 10.8
= - 51.776 kJ/<span>mol
I hope the procedure is clear enough for you to understand.</span>
