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alex41 [277]
3 years ago
12

Which one of the following would you expect to dissolve in water? limonene sucrose oil atmospheric oxygen none of the above

Chemistry
1 answer:
sdas [7]3 years ago
3 0

-----------sucrose----------------

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A protein is Select one: a. a saturated ester of glycerol. b. a polysaccharide. c. an aromatic hydrocarbon. d. a polymer of amin
Rzqust [24]

Answer:

D

Explanation:

The building blocks or monomers of proteins are called amino acids. There are 20 different kinds of amino acids. The amino acids form long chains that are proteins. Therefore, proteins are polymers of amino acids.

Proteins are very important for the body because they have many different roles. They provide structure for tissues, act as enzymes, hormones and antibodies, aid in transportation and fluid regulation.

Therefore, the correct answer is D. a polymer of amino acids.

7 0
2 years ago
I have 345 mL of a 1.5 M NaCl solution. If I boil the water until the volume of the solution is 250 mL, what will the molarity o
likoan [24]
We know that molarity = mol/L, so:

1.5 M = x mol/0.345 L

1.5 M * 0.345 L = x mol => 0.5175 mol

0.5175 mol/0.250 L = 2.07 M

Your new molarity of the solution will be 2.07 M.
6 0
3 years ago
4. Is it possible for two different compounds to be made from the exact same two elements? Why or why not? With a limited number
densk [106]

no it is not possible, because they both have the same number of valence electrons in each element. in a compound you are supposed to have two or more elements that have different numbers of valence electrons so when put together they for a compound.

3 0
3 years ago
What is the IUPAC name for the compound shown below? ch3ch2ch2cnhch2ch3
Nataly_w [17]

We need the  IUPAC name of the given compound.

The IUPAC name is: Hexan-3-imine.

The molecule has six carbon atoms in its skeleton. C=NH bond is attached to the skeleton at 3-position.

The functional group present in this molecule is imine (C=NH).

3 0
3 years ago
Read 2 more answers
Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
RoseWind [281]

Answer:

M_{per}= 52.86

W_{per}=47.14

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

m_{met1}=200 kg * 0.4= 80 kg

m_{wat1}=200 kg * 0.6= 120 kg

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

m_{met2}=150 kg * 0.7= 105 kg

m_{wat2}=150 kg * 0.3= 45 kg

Final mixture:

m_{metF=80 kg + 105 kg= 185 kg

m_{watF}=120 kg + 45 = 165 kg

M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86

W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0
3 years ago
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