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1 year ago

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A steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds. Find the force act

ing on the marble.

1 answer:

emmasim [6.3K]1 year ago

3 0

After finding acceleration, it is found that 0.02 N of force is acting on the marble

<h3>What is Force ?</h3>

Force can simply be defined as a pull or push. It is the product of mass and acceleration of the object. It is a vector quantity and it is measured in Newton.

Given that a steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds.

The parameters to consider are;

m = 0.05 Kg

u = 0

s = 0.25 m

t = 1.2 s

a = ?

F = ?

Before we find the force acting on the marble, let us first find the acceleration by using the formula: s = ut + 1/2at²

Substitute all the parameters into the formula

0.25 = 0 + 1/2 × a × 1.2²

0.25 = 1/2 × a × 1.44

0.25 = 0.72a

a = 0.25/0.72

a = 0.35 m/s²

The force acting on the marble will be ;

F = ma

F = 0.05 × 0.35

F = 0.017

F = 0.02 N

Therefore, the force acting on the marble is 0.02 N

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A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre

AleksandrR [38]

Answer:

A) 1568.60 Hz

B) 1437.15 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

$f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\$

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

$f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz$

B)Here the Source is moving away the receiver(C+Vs)

and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser

$f_(observed)=\frac{C}{C+V_s} *f_(emmited)\\=\frac{343}{343+15}*1500\\ =1437.15 Hz$

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3 years ago

What two forces are balanced in what we call gravitational equilibrium? What two forces are balanced in what we call gravitation

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Question:

What two forces are balanced in what we call gravitational equilibrium?

A) the electromagnetic force and gravity

B) outward pressure and the strong force

C) outward pressure and inward gravity

D) the strong force and gravity

E) the strong force and kinetic energy

Answer:

The correct answer is C) Outward Pressure and Inward gravity

Explanation:

Gravitational equilibrium is a balance between the inward pull of gravity and the outward push of internal gas pressure. It also refers to the condition of a star in which the weight of overlying layers at each point is balanced by the total pressure at that point.

As the weight increases in the lower layers of the sun, the pressure also increases to maintain this balance. So you find that the outward push of pressure balances the inward pull of gravity thus creating an equilibrium.

Why is gravitational equilibrium important?

The simple answer is <u>balance. </u> If for instance the sun as a stable star (which has gravitational equilibrium) loses it's balance, it becomes highly unstable and prone to violent outbursts. These outbursts are caused by the very high radiation pressure at the star's upper layers, which blows significant portions of the matter at the "surface" into space during eruptions that may rage for several years. Of course such a condition is adverse to the existence and support of life.

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3 years ago

A distant astronomical object (a quasar) is moving away from us at half the speed of light. what is the speed of the light we re

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For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar is mathematically given as c = 3x108 m/s

<h3>What is the speed of light?</h3>

Generally, the equation for the is mathematically given as

The speed of light can be said to be measured to be approximately the value c = 3x108 m/s

.

In conclusion, An will not influence 3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to 3x108 m/s

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2 years ago

A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?

iris [78.8K]

Answer:

$\Delta x=22.67786838m$

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

$y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2$ (1)

Where:

$y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis$

$y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis$

$v_o=initial\hspace{3}velocity$

$t=travel\hspace{3}time$

$g=gravity\hspace{3}constant$

$\theta=Initial\hspace{3}launch\hspace{3}angle$

In this case:

$\theta=0$

Because the dog jumps horizontally

Let's asume the gravity constant as:

$g=9.8$

$y=0$

Because when the dog reach the base the height is 0

$y_o=70$

$v_o=6$

Now let's replace the data in (1)

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Finally let's find the horizontal displacement using this equation:

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Replacing the data:

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3 years ago

If the same elevator accelerates downwards

PilotLPTM [1.2K]

The upward force exerted by the elevator floor on the passenger is 7.6 times mass of the passenger.

<h3>What is force?</h3>

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Given in question elevator accelerates downwards with an acceleration of 1.2 m/s². There is acceleration due to gravity working downward which is 9.8 m/s².

So, net acceleration due to gravity is given as 9.8 - 1.2 = 7.6 m/s²

The upward force exerted by the elevator floor on the passenger is mass times acceleration, 7.6 times mass of passenger.

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1 year ago