Answer:
some symptoms can be lack of energy, and dizziness.
Explanation:
The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
Learn more about heat pump here :
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One possible unit is liter, which is a basic unit in metric system. 1 liter=10 cm^3, or 0.001 m^3, so we also know that other possible units include cubic centimeters or cubic meters, which are derived units, since they are derived from basic unit, meter, representing the length, breadth, and height of the cuboid.
The pressure inside the container will be <u>9.39×10⁴Pa</u>
At constant volume, the pressure in a container is directly proportional to its absolute temperature.
If air in a container is sealed at 20⁰C at a pressure equal to the atmospheric pressure and cooled to 2.00⁰C, the pressure inside the container falls.
Convert the temperature in Celsius to Kelvin.
Use the expression for the pressure law.
Substitute 100,000 Pa for P₁, 293.16 K for T₁ and 275.15K for T₂.
The pressure in the container (correct to 2 sf) is <u>9.39×10⁴Pa</u>
