Question

Calculate the acceleration of Josh riding his bicycle in a straight line that speeds up from 4 m/s to 6 m/s in 5 seconds

Answer 1

Answer:

$a=0.4m/s^2$

Explanation:

The formula for calculating acceleration is as follows:

$a=\frac{v_{f}-v_{i}}{t}$

where $v_{f}$ is the final velocity, $v_{i}$ the initial velocity, an $t$ is the time in wich the velocity changed.

For this case:

$v_{f}=6m/s$

$v_{i}=4m/s$

$t=5s$

Thus the acceleration is:

$a=\frac{6m/s-4m/s}{5s}$

$a=\frac{2m/s}{5s}$

$a=0.4m/s^2$

The acceleration of Josh is: $a=0.4m/s^2$

Answer 2

Answer:

U=4m/s

V=6m/s

T=5s

Acceleration =v-u/t

6-4/5

=2/5 metre/second(square).