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telo118 [61]
1 year ago
10

two workers are sliding 260 kg crate across the floor. one worker pushes forward on the crate with a force of 450 n while the ot

her pulls in the same direction with a force of 370 n using a rope connected to the crate. both forces are horizontal, and the crate slides with a constant speed. what is the crate's coefficient of kinetic friction on the floor?
Physics
1 answer:
balu736 [363]1 year ago
6 0

To find out the kinetic friction, using the coefficient friction formula.

What is kinetic friction?

A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.

What is coefficient friction?

A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.

UK

U-coefficient of friction

K-Kinetic friction

Using UK

450+370-f=m*o

f=820=UK*260*9.8

UK=2.548

820/2.548

UK= 321.8210361

Therefore the coefficient of kinetic friction is 321.8210361

Learn more about Kinetic friction from the given link.

brainly.com/question/14111192

#SPJ4

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Answer:

The answer to the question is

The distance d, which locates the point where the light strikes the bottom is   29.345 m from the spotlight.

Explanation:

To solve the question we note that Snell's law states that

The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction

n₁sinθ₁ = n₂sinθ₂

y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and

θ₁ =  14.511 °

n₁ = 1.0003 = refractive index of air

n₂ = 1.33 = refractive index of water

Therefore sinθ₂ =  \frac{n_1sin\theta_1}{n_2}  = \frac{1.003*0.251}{1.33} = 0.1885 and θ₂ = 10.86 °

Since the water depth is 4.0 m we have tanθ₂ = \frac{4}{x_2} or x₂ = \frac{4}{tan\theta_2 } =\frac{4}{tan(10.86)} = 20.845 m

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show mathematically why an 80,000 pound ( 36,000 kg ) big rig taveling 2 mph (0.89 m/s) has the SAME MOMENTUM as a 4,000 pound (
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The momentum value for both Big rig and sport utility vehicle are the same as 16000 pound mph

<u>Explanation:</u>

Given data are as follows  

For Big rig, Mass = 80,000 pound (36,000 kg)  

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where mph is meter per hour

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velocity = 40 mph (18 m/s)

The formula to find the Momentum of an object is

Momentum = Mass × Velocity (Kilogram meter per second)

Momentum for Big rig = 80,000 × 2 (pound mph)

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Hence it is mathematically proved that  

The momentum of big rig = The momentum of sport utility vehicle

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