A 125-g metal block at a temperature of 93.2 °C was immersed in 100. g of water at 18.3 °C. Given the specific heat of the metal
1 answer:
Answer:
34.17°C
Explanation:
Given:
mass of metal block = 125 g
initial temperature = 93.2°C
We know
..................(1)
Q= Quantity of heat
m = mass of the substance
c = specific heat capacity
c = 4.19 for H₂O in
= change in temperature
Now
The heat lost by metal = The heat gained by the metal
Heat lost by metal =
Heat gained by the water =
thus, we have
=
⇒
Therefore, the final temperature will be = 34.17°C
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