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natali 33 [55]
2 years ago
14

if a stone is projected at an angle of 50 degrees to the horizontal with an initial velocity of 50m/s, what is the vertical comp

onent of the initial velocity
Physics
1 answer:
Vilka [71]2 years ago
3 0

Answer:

38.3 m/s

Explanation:

To find vertical component of initial velocity, you'd have to use sine ratio:

\displaystyle{\sin \theta = \dfrac{u_y}{u}}

\displaystyle{u_y} is vertical component of initial velocity and \displaystyle{u} is initial velocity given which is 50 m/s.

A stone is projected at an angle of 50 degrees so \displaystyle{\theta} = 50°. Substitute in the formula:

\displaystyle{\sin 50^{\circ} = \dfrac{u_y}{50}}\\\\\displaystyle{50 \sin 50^{\circ} = u_y}\\\\\displaystyle{u_y = 38.3 \ \, \sf{m/s}}

Therefore, the vertical component of initial velocity is approximately 38.3 m/s

(The picture is also attached for visual reference!)

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Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0
DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

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So \frac{1}{2}\times 1.7\times v^2=14

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3 years ago
A boy standing on a bridge above a river throws stone A vertically upward with an initial velocity =15m/s.2 seconds later he dro
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I'm not sure if this is correct but it's what I'll do

This is free-fall problem.
Stone A is thrown upward, at the point it falls down to the place where it was thrown, the velocity is -15m/s.

Now I choose the bridge is the origin. From the bridge, stone A and B fall the same distance which means Ya = Yb ( vertical distance )

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= -15t - 30 + 4.5(t^2 + 4t + 4)
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Yb = Vo(t) + 1/2a(t)^2
= 0 + 4.5t^2

4.5t^2 = 4.5t^2 +3t - 12
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4 = t

Time for Stone B is 4s
Time for Stone A is 6s

7 0
3 years ago
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