Answer:
Diaplacement s=1.80km
Final velocity v=360km/h
It starts from rest. So, initial velocity u=0
We need to find the constant acceleration (a).
using the equation of motion v
2
=u
2
+2as
360
2
=0
2
+2×a×1.8
a=
3.6
360×360
a=36000km/h
2
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Answer: large reflector located in orbit above the Earth's atmosphere
Explanation:
Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.
It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.
Answer:
<em>C.) 7.9 km</em>
Explanation:
<u>Distance and Displacement
</u>
An object who constantly travels for some distances at defined periods of time has a total distance as the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.
Dr. Suarez walks 2.8 km north and then 5.1 km south. The total distance is simply the sum of both distances: 2.8 km + 5.1 km = 7.9 km.
Note the distance does not have any direction (north or south), it's just the number.
Answer: C.) 7.9 km