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Setler [38]
3 years ago
12

A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?

Physics
1 answer:
antiseptic1488 [7]3 years ago
6 0
Using p = mv 3 = 1× v v = 3m/s
You might be interested in
A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice w
Alenkasestr [34]

Answer:

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

Q = mc\Delta T

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

\Delta T = Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

Q = mc\Delta T

Q = 50*0.11*(80-0)

Q = 440cal

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

Q_2 = mL = 80*m

How Q_1=Q_2, so

80m=440

m=\frac{440}{80}

m = 5.5g

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

7 0
3 years ago
The potential difference between two equipotential lines 5.0 mm apart has a value of 1.2 V, calculate the electric field value.
jonny [76]

Answer:

The electric field value is 240 N/C

Explanation:

Given that,

Distance = 5.0 mm

Potential difference = 1.2 V

We need to calculate the electric field value

Using formula of potential difference

\Delta V=Ed

E=\dfrac{\Delta V}{d}

Where, E = electric field

V = potential difference

d = distance

Put the value into the formula

E=\dfrac{1.2}{5.0\times10^{-3}}

E= 240\ N/C

Hence, The electric field value is 240 N/C

6 0
3 years ago
The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?
RoseWind [281]

Answer:

E = 2.9775\times10^5 J

Explanation:

Given:  The latent heat of fusion for Aluminum is L = 3.97\times10^5  J/Kg

mass to be malted m = 0.75 Kg

Energy require to melt E = mL

E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J

Therefore, energy required to melt 0.75 Kg aluminum

E = 2.9775\times10^5 J

5 0
3 years ago
What kind of circuit is the one shown below?
lions [1.4K]

Answer:

The given circuit diagram shows parallel circuit.

Explanation:

In this circuit diagram two bulbs are connected in parallel combination because current flows from the battery gets bifurcated at the junction. Thus, two bulbs are connected in parallel combination.

This parallel combinations of bulbs then connected to the battery given in the diagram. So, the combinations of bulbs are connected in parallel combinations with the battery.

Hence, both bulbs and battery are connected in parallel combinations with each other.

The circuit diagram shown in figure is parallel.


8 0
3 years ago
Read 2 more answers
A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces.
Sunny_sXe [5.5K]

Answer: 240\ rad/s^2

Explanation:

Given

Length of beam l=2\ m

mass of beam m=5\ kg

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

\tau =F\times l=200\times 2=400\ N.m

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

I=\dfrac{ml^2}{12}=\dfrac{5\times 2^2}{12}\\\\I=\dfrac{5}{3}\ kg.m^2

Torque is the product of moment of inertia and angular acceleration

\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2

7 0
3 years ago
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