A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?

A hydrogen atom has its electron in the n = 6 level. the radius of the electron's orbit in the bohr model is 1.905 nm.

gayaneshka [121]

Are there any options or is it not multiple choice.

5 0

2 years ago

How does the use of simple machines affect force and distance when work is done?

bazaltina [42]

Answer:

Explanation:

Machines simply make work easier to do. They increase the amount of force exerted on a body and also the distance through which the force is applied. Also, they can also change the direction through which force on them is applied in order to produce much more work.

Work done = force x distance

The input force in a machine is attenuated to yield even more force. This is the purpose of designing a simple machine. When the force increases, more work would be produce with our little effort applied on the body.

Work done is a function of the force applied on a body and the distance through which it moves.

8 0

3 years ago

The orbital period of an object is 2 x 10^7 and its total radius is 4 x 10^4 m.

SVETLANKA909090 [29]

Answer:

12566

Explanation:

Use formula: vt=2pir/t

7 0

3 years ago

Read 2 more answers

A helicopter lifts a 81 kg astronaut 19 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/

nexus9112 [7]

Answer:

a) The work done on the astronaut by the force from the helicopter is $W_{h}=16087.68\ J$ .

b) The work done on the astronaut by the gravitational force is $W_{g}=-15082.2\ J$ .

Explanation:

We are told that the mass of the astronaut is $m=81\ kg$ , the displacement is $\Delta x=19\ m$ , the acceleration of the astronaut is $|\vec{a}|=\frac{g}{15}$ and the acceleration of gravity is $g=9.8\ \frac{m}{s^{2}}$ .

We suppose that in the vertical direction the force from the helicopter $F_{h}$ is upwards and the gravitational force $F_{g}$ is downwards. From the sum of forces we can get the value of $F_{h}$ :

$F_{h}-F_{g}=m.a$

$F_{h}-mg=m.\frac{g}{15}$

$F_{h}=mg(1+\frac{1}{15})$

$F_{h}=(\frac{16}{15}).81\ kg.\ 9.8\ \frac{m}{s^{2}}\ \Longrightarrow\ F_{h}=846.72\ N$

We define work as the product of the force, the displacement of the body and the cosine of the angle $\theta$ between the direction of the force and the displacement of the body: