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Likurg_2 [28]
1 year ago
7

Table salt contains 39.33 g of sodium per 100 g of salt. The U.S. Food and Drug Administration (FDA) recommends that adults cons

ume less than 2.40 g of sodium per day. A particular snack mix contains 1.30g of salt per 100 g of the mix.What mass of the snack mix can you consume and still be within the FDA limit?
Chemistry
1 answer:
Naya [18.7K]1 year ago
7 0

The  individual can consume less than 184.6 g of the snack mix and still be within the FDA limit of salt consumption.

<h3>What is the mass of snack that can be consumed within the limit of sodium intake?</h3>

The mass of the snack mix that the individual can consume and still be within the FDA limit is calculated as follows:

U.S. Food and Drug Administration (FDA) recommends of sodium intake = less than 2.40 g of sodium per day.

Amount of salt in 100 g of snack mix = 1.30 g

Mass of snack that will contain 2.40 g of sodium = 2.40 * 100g/1.30 = 184.6 g of snack mix

Therefore, the individual can consume less than 184.6 of the snack mix and still be within the FDA limit of salt consumption.

In conclusion, the FDA recommends that an individual take in less than 2.40 g of sodium per day from their diet.

Learn more about salts at: brainly.com/question/23463868

#SPJ1

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4 0
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Yasmin's teacher tells her that the solubility of salt is 360 g/L at room temperature (25 °C). How can Yasmin make an unsaturate
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6 0
4 years ago
Read 2 more answers
a 25.0-ml volume of a sodium hydroxide solution requires 19.6 ml of a 0.189 m hydrochloric acid for neutralization. a 10.0- ml v
Rashid [163]

<u>Concentration of NaOH = 0.148 molar, M</u>

<u>Concentration of H3PO4 = 0.172 molar, M</u>

<u></u>

Concentration x Volume  will give the number of moles of solute in that volume.  C*V = moles

Concentration  has a unit of (moles/liter).  When multiplied by the liters of solution used, the result is the number of moles.

Original HCl solution:  (0.189 moles/L)*(0.0196 L)= 0.00370 moles of HCl

The neutralization of 25.0 ml of sodium hydroxide, NaOH, requires 0.00370 moles of HCl.  The reaction is:

  NaOH + HCl > NaCl and H2O

This balanced equation tells us that neutralization of NaOH with HCl requires the same number of moles of each.  We just determined that the  moles of HCl used was 0.00370 moles.  Therefore, the 25.0 ml solution of NaOH had the same number of moles:  0.00370 moles NaOH.

The 0.00370 moles of NaOH was contained in 25.0 ml (0.025 liters).  The concentration of NaOH is therefore:  

    <u>(0.00370 moles of NaOH)/(0.025 L) = 0.148 moles/liter or Molar, M</u>

====

The phosphoric acid problem is handled the same way, but with an added twist.  Phosphoric acid is H3PO4.  We learn the 34.9 ml of the same NaOH solution (0.148M) is needed to neutralize the H3PO4.  But now the acid has three hydrogens that will react.  The balanced equation for this reaction is:

  H3PO4 + 3NaOH = Na3PO4 + 3H2O

Now we need <u><em>three times</em></u> the moles of NaOH to neutralize 1 mole of H3PO4.

The moles of NaOH that were used is:

  (0.148M)*(0.0349 liters) = 0.00517 moles of NaOH

Since the molar ratio of NaOH to H3PO4 is 3 for neutralization, the NaOH only neutralized (0.00517)*(1/3)moles of H3PO4 = 0.00172 moles of H3PO4.

The 0.00172 moles of H3PO4 was contained in 10.0 ml.  The concentration is therefore:

     (0.00172 moles H3PO4)/(0.010 liters H3PO4)

<u>Concentration of H3PO4 = 0.172 molar, M</u>

 

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