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Iteru [2.4K]
1 year ago
15

Not all projects that engineers work on will have human factors involved.

Engineering
1 answer:
Sliva [168]1 year ago
6 0

Projects that don't have human factors involved are:

  • The Use of Artificial Intelligence to Power Road Construction Robots;
  • End to End robotic Automobile production line.

Other projects that require human factors are;

  • Traditional road construction projects;
  • Traditional building construction projects.

<h3>What are the human factors for Road Construction?</h3>

The role of human factors includes but is not limited to:

  • Operation of Heavy-Duty Vehicles
  • Human Resources (taking care of people)
  • Finance operations  (Finance and Accounting) etc.

At construction sites, excavation is one of the roles of humans. Another instance is injuries, compensation, etc is the work of the Human Resources Officer.

Human factors include environmental, organizational, and job elements, as well as human and individual qualities that influence workplace behavior and can have an impact on health and safety.

Human-factors engineering has been applied to simple equipment such as highway signs, telephone sets, hand tools, and stoves, as well as a wide range of contemporary, sophisticated complexes such as data systems, automated warehouses, and factories. robots, and space vehicles.

Learn more about Road Construction:
brainly.com/question/25795065
#SPJ1



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3 MAOP stands for which of the following?
raketka [301]

Answer:

MAOP Master of Arts in Organizational Psychology (various universities)

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Explanation:

3 0
3 years ago
it is used to meusure the amount of electric current. A.clamp meter. B .micrometer C steel rule D. electric meter​
Marianna [84]

Answer:

<em>Option D </em>

<em>Electric meter is used to </em><em>measure</em><em> the amount of electric current</em>

6 0
3 years ago
a) A total charge Q = 23.6 μC is deposited uniformly on the surface of a hollow sphere with radius R = 26.1 cm. Use ε0 = 8.85419
dusya [7]

Answer:

(a) E = 0 N/C

(b) E = 0 N/C

(c) E = 7.78 x10^5 N/C

Explanation:

We are given a hollow sphere with following parameters:

Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C

R = radius of sphere = 26.1 cm = 0.261 m

Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²

The formula for the electric field intensity is:

E = (1/4πεo)(Q/r²)

where, r = the distance from center of sphere where the intensity is to be found.

(a)

At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.

<u>E = 0 N/C</u>

(b)

Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).

<u>E = 0 N/C</u>

(c)

Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:

E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]

<u>E = 7.78 x10^5 N/C</u>

4 0
3 years ago
Air enters an adiabatic compressor through 0:5m2 opening and exhausts through a 0:2m2 opening. The inlet conditions of air are 2
gladu [14]

Answer:

i) 43.55 kg/s

ii) 40 m/s

iii)  -199.32 KW

Explanation:

To resolve the above question we have to make some assumptions :

  • mass flow  through the system is constant
  • The only interactions that are between the system and the surrounding are work and heat
  • The fluid is uniform

i) first we have to determine the mass flow rate of the air

M = (\frac{P1}{RT1} )A1v1

    = ( \frac{200}{0.287*325} ) 0.5 * V1 ---------- (1) hence  M = 43.55 kg/s

ii) using this relationship : A1V1 = A2V2 hence V1 = (0.2/0.5) * 100 = 40m/s (    inlet velocity )

input this value into equation 1

iii) Next we will determine the power required to run compressor

attached below

power required = -199.32 KW ( this value indicates that there is power supplied )

8 0
3 years ago
In pea plants, tall height is dominant over short height. How can two tall plants result in a short offspring.
MatroZZZ [7]
I think if both the parents are heterozygous. Then if you do a punnet square the last box would be tt. There you go!
3 0
3 years ago
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