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sleet_krkn [62]
3 years ago
5

Calculate the number of vacancies per cubic meter for some metal, M, at 749°C. The energy for vacancy formation is 0.86 eV/atom,

while the density and atomic weight for this metal are 5.94 g/cm3 (at 749°C) and 80.09 g/mol, respectively.
Engineering
1 answer:
kogti [31]3 years ago
5 0

Answer:

Number of Vacancies = 1.22E23

Explanation:

Given

Energy for formation = 0.86 eV/atom (Q)

Density = 5.94 g/cm³

Atomic weight = 80.09 g/mol

Temperature = 749°C = 1022K

Avogadro's Constant = 6.022E23 atoms/mol

Boltzmann constant = 8.62E-5 eV/K (k)

Determination of the number of vacancies per cubic meter in metal, M at 749C (1022 K) is given by:

N exp (-Q/kT)

Where N = 6.022E23 * 5.94/ 80.09

N = 4.47E22

So, Number of Vacancies = 4.47E22 exp (-0.86 / (8.62E-5 * 1022))

= 4.47E22 exp (-9.76)

= 1.2150719773211E23

Number of Vacancies = 1.22E23 ------ Approximated

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Answer:

41.67amps

Explanation:

v*a=w

120*a=5000

5000/12=41.67

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Of the following answers, which is NOT a way for employees to control exposure routes?
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Answer:  Of the following answers, which is NOT a way for employees to control exposure routes?

Explanation:

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3 years ago
Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi
yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2)  int arr[] = new int[size_of_array];

        int increment = 100;

        for (int i = 0; i < size_of_array; i++) {

       arr[i] = increment * i;

       }

      return arr;

3) for (int i = 0; i < myArray.length; i++) {

      System.out.println(myArray[i]);

4)  OneDimensionalArrays result = new OneDimensionalArrays();

    result.createIntegers(num);

    result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

   

   int[] createIntegers(int size_of_array)

   {

      //*******  FILL IN CODE *********

      // Your code will create an array of ints as large as specified in size_of_array

      // Fill the array in with the values: 0, 100, 200, 300, ....

      // Return the array that you just created

   }

   void printArray(int[] myArray)

   {

      //*******  FILL IN CODE *********

       // Print out your array with one number per line.  Get the size of the

       // array from the "myArray" parameter (no hard coding the size)

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       //*******  FILL IN CODE *********

       // Construct an instance of the OneDimensionalArrays class

       // Using this object instance, call createIntegers to create

       // an array of integers.  Don't forget to save the results

       // Then call the printArray method to print out the contents

       // of your array.

       }

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

  private static int[] arr;

  int[] createIntegers(int size_of_array) {

       int arr[] = new int[size_of_array];

       int increment = 100;

       for (int i = 0; i < size_of_array; i++) {

             arr[i] = increment * i;    

       }

       return arr;

   }

   void printArray(int[] myArray) {

       for (int i = 0; i < myArray.length; i++) {

           System.out.println(myArray[i]);          

       }

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       OneDimensionalArrays result = new OneDimensionalArrays();

       result.createIntegers(num);

       result.printArray(arr);

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}

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3 years ago
Cast-in-place concrete beams are identified on a plan view with letters and numbers that correspond to the ___.
Alona [7]

Cast-in-place concrete beams are identified on a plan view with letters and numbers that correspond to the beam schedule.

<h3>What are concrete beams?</h3>

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Cast-in-place concrete beams are identified on a plan view with letters and numbers corresponding to the beam schedule.

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4 0
2 years ago
assume a five layer network model. There are 700 bytes of application data. There is a 20 bye header at the transport layer, a 2
amm1812

Answer: The overhead percentage is 7.7%.

Explanation:

We call overhead, to all those bytes that are delivered to the physical layer, that don't carry real data.

We are told that we have 700 bytes of application data, so all the other bytes are simply overhead, i.e. , 58 bytes composed by the transport layer header, the network layer header, the 14 byte header at the data link layer and the 4 byte trailer at the data link layer.

So, in order to assess the overhead percentage, we divide the overhead bytes between the total quantity of bytes sent to the physical layer, as follows:

OH % = (58 / 758) * 100 = 7.7 %

4 0
3 years ago
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