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sleet_krkn [62]
2 years ago
5

Calculate the number of vacancies per cubic meter for some metal, M, at 749°C. The energy for vacancy formation is 0.86 eV/atom,

while the density and atomic weight for this metal are 5.94 g/cm3 (at 749°C) and 80.09 g/mol, respectively.
Engineering
1 answer:
kogti [31]2 years ago
5 0

Answer:

Number of Vacancies = 1.22E23

Explanation:

Given

Energy for formation = 0.86 eV/atom (Q)

Density = 5.94 g/cm³

Atomic weight = 80.09 g/mol

Temperature = 749°C = 1022K

Avogadro's Constant = 6.022E23 atoms/mol

Boltzmann constant = 8.62E-5 eV/K (k)

Determination of the number of vacancies per cubic meter in metal, M at 749C (1022 K) is given by:

N exp (-Q/kT)

Where N = 6.022E23 * 5.94/ 80.09

N = 4.47E22

So, Number of Vacancies = 4.47E22 exp (-0.86 / (8.62E-5 * 1022))

= 4.47E22 exp (-9.76)

= 1.2150719773211E23

Number of Vacancies = 1.22E23 ------ Approximated

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EastWind [94]

Answer:

(1). False, (2). True, (3). False, (4). False, (5). True.

Explanation:

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(1). In contouring, it is necessary to measure position and not velocity for feedback.

ANSWER : b =>False. IT IS NECESSARY TO MEASURE BOTH FOR FEEDBACK.

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ANSWER: a=> True.

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ANSWER: b => False

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8 0
3 years ago
A transformer winding contains 900 turns of wire which creates 400 ohms of primary importance how many terms of the same size wi
Eduardwww [97]

Answer: 255

255 turns are required to create 25 ohms of  secondary impedance.

Explanation:

Given that,

Number of turns in primary wire N₁ = 900

impedance on Primary wire Z₁ = 400 ohms

Number of turns in Secondary wire N₂ = ?

impedance on Secondary wire Z₂ = 25 ohms

we know that, the relationship between turn and impedance is

Zp / Zs = ( Np / Ns )²

(Primary impedance / secondary impedance) = Number of turns in primary wire / Number of turns in secondary wire)²

there fore

Z₁ / Z₂ = ( N₁ / N₂ )²

Now we substitute

( 400 / 25 ) = ( 900 / N₂ )²

400 / 25 = 900² / N₂²

we cross multiple to get our N₂

400 × N₂² =  900² × 25

N₂² = ( 900² × 25 ) / 400

N₂² = ( 810000 × 25 ) / 400

N₂² = 20250000 / 400

N₂² = 50625

N₂ = √50625

N₂ = 225

Therefore 255 turns are required to create 25 ohms of  secondary impedance.

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What are the chemical properties of metals
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Answer:

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