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frez [133]
3 years ago
5

A steel bolt has a modulus of 207 GPa. It holds two rigid plates together at a high temperature under conditions where the creep

of the steel is described by the equation:ε=ε0σσ0nwhere n= 3, andε=127.8 10−×/s when σ= 28 MPa. The bolt is initially tightened to a stress of 69 MPa. What is the stress in it after 1 year? (14 MPa)

Engineering
1 answer:
VikaD [51]3 years ago
7 0

Answer:

14.36((14MPa) approximately

Explanation:

In this question, we are asked to calculate the stress tightened in a bolt to a stress of 69MPa.

Please check attachment for complete solution and step by step explanation

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Answer:

Answer to the following question is as follow.

Explanation:

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8 0
3 years ago
An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate is found to be 1% pe
LenaWriter [7]

Answer:

a) Q = 251.758 kJ/mol

b) creep rate is    = 1.751 \times 10^{-5} \% per hr

Explanation:

we know Arrhenius expression is given as

\dot \epsilon =Ce^{\frac{-Q}{RT}

where

Q is activation energy

C is pre- exponential constant

At 700 degree C creep rate is\dot \epsilon = 5.5\times 10^{-2}% per hr

At 800 degree C  creep rate is\dot \epsilon = 1% per hr

activation energy for creep is \frac{\epsilon_{800}}{\epsilon_{700}} = = \frac{C\times e^{\frac{-Q}{R(800+273)}}}{C\times e^{\frac{-Q}{R(700+273)}}}

\frac{1\%}{5.5 \times 10^{-2}\%} = e^{[\frac{-Q}{R(800+273)}] -[\frac{-Q}{R(800+273)}]}

\frac{0.01}{5.5\times 10^{-4}} = ln [e^{\frac{Q}{8.314}[\frac{1}{1073} - \frac{1}{973}]}]

solving for Q we get

Q = 251.758 kJ/mol

b) creep rate at 500 degree C

we know

C = \epsilon e^{\frac{Q}{RT}}

    =- 1\% e{\frac{251758}{8.314(500+273}} = 1.804 \times 10^{12} \% per hr

\epsilon_{500} = C e^{\frac{Q}{RT}}

                         = 1.804 \times 10^{12}  e{\frac{251758}{8.314(500+273}}

                         = 1.751 \times 10^{-5} \% per hr

4 0
3 years ago
Under EPA's regulations, which of the following methods can be used to pressurize an R11 or R123 system for the purpose of openi
Natasha2012 [34]

Answer:

(A) Adding Nitrogen

Explanation:

R11 or R123 are flammable substance under certain conditions when mixed with Oxygen, adding Nitrogen is a safety procedure used in displacing any R11 or R123 which are considered as hazardous when mixed with Oxygen.

7 0
3 years ago
For a Cu-Ni alloy containing 53 wt.% Ni and 47 wt.% Cu at 1300°C, calculate the wt.% of the alloy that is solid and wt.% of allo
Zina [86]

Answer:

Hello your question is incomplete attached below is the complete question

answer: wt.% of alloy that is solid = 61.5%

             wt.% of allot that is liquid = 38.5%

Explanation:

To determine the wt.% of the alloy that is solid

= \frac{R}{R +S } * 100

=  \frac{53-45}{58-45} * 100  = 61.5%

To determine the wt.% of the alloy that is liquid

= \frac{S}{S+R} * 100\\

= \frac{58-53}{58-45} *100 = 38.5%

attached below is a free hand sketch as well

7 0
3 years ago
3. What is the mechanical advantage of the pulley system shown below? HII TAI 190 O A1 O E.2 OC.3 OD 4​
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Answer:

I don't know ☺️☺️☺️❌‼️

Explanation:

I don't understand this question

7 0
3 years ago
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