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julsineya [31]
4 years ago
11

Carbon dioxide (CO2) at 1 bar, 300 K enters a compressor operating at steady state and is compressed adiabatically to an exit st

ate of 10 bar, 520 K. The CO2 is modeled as an ideal gas, and kinetic and potential energy effects are negligible. For the compressor, determine (a) the work input, in kJ per kg of CO2 flowing, (b) the rate of entropy production, in kJ/K per kg of CO2 flowing, and (c) the isentropic compressor efficiency.

Engineering
1 answer:
Zielflug [23.3K]4 years ago
6 0

Answer:

A.) 0.08 kJ/kg.K

B.) 207.8 KJ/Kg

C.) 0.808

Explanation:

From the question, the use of fluids mechanic table will be required. In order to get the compressor processes, the kinetic energy and the potential energy will be negligible while applying the ideal gas model.

Since the steam is a closed system, the carbon dioxide will be compressed adiabatically.

Please find the attached files for the solution and the remaining explanation.

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A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is
patriot [66]

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)=20 W/m^2-K

Air temperature =75 F

surface area(A)=7.5 m^2

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7 0
3 years ago
Consider a vortex filament of strength in the shape of a closed circular loop of radius R. Obtain an expression for the velocity
zysi [14]

Answer:

<em>v</em><em> </em>= T/(2R)

Explanation:

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R = radius

T = strength

From Biot - Savart Law

d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³

Velocity induced at center

<em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>r</em>)/r³

⇒   <em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>R</em>)/R³  (<em>k</em>)        <em>k</em><em>:</em> unit vector perpendicular to plane of loop

⇒   <em>v </em>= (T/4π)(1/R²) ∫ dl

If l ∈  (0, 2πR)

⇒   <em>v </em>= (T/4π)(1/R²)(2πR)  (<em>k</em>)    ⇒   <em>v </em>= T/(2R)  (<em>k</em>)  

3 0
4 years ago
3. If nothing can ever be at absolute zero, why does the concept exist?
Tanzania [10]

The absolute zero in temperature refers to the minimal possible temperature. It is the temperature at which the molecules of a system stop moving, so it is a really useful reference point.

<h3>Why absolute zero can't be reached?</h3>

It would mean that we need to remove all the energy from a system, but to do this we need to interact with the system in some way, and by interacting with it we give it "some" energy.

Actually, from a quantum mechanical point of view, the absolute zero has a residual energy (so it is not actually zero) and it is called the "zero point". This happens because it must meet <u>Heisenberg's uncertainty principle</u>.

So yes, the absolute zero can't be reached, but there are really good approximations (At the moment there is a difference of about 150 nanokelvins between the absolute zero and the smallest temperature reached). Also, there are a lot of investigations near the absolute zero, like people that try to reach it or people that just need to work with really low temperatures, like in type I superconductors.

So, concluding, why does the concept exist?

  • Because it is a reference point.
  • It is the theoretical temperature at which the molecules stop moving, defining this as the <u>minimum possible temperature.</u>

If you want to learn more about the absolute zero, you can read:

brainly.com/question/3795971

3 0
3 years ago
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