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Dmitry [639]
1 year ago
9

HII!!! I need serious help with this assignment so I'm offering half my points so pLS accurately answer!! SO for this assignment

i need to know the order it goes in conducter, battery, or light bulb, battery conducter, light bulb, (ETC...etc....)
Please tell me which order they go in! Also please tell me why it is correct ??

Physics
1 answer:
ehidna [41]1 year ago
3 0

Answer:

Hey, I'm not sure I understand exactly what your assignment is but hopefully this helps . . .

put the other end against the side of the bubls base to light up the light bulb.

This will act as the bulbs conductor, lighting up bc you are making a complete electrical circuit between positive and negative terminals of the battery.

Ok hopefully this helps you out

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Can someone solve this problem and explain to me how you got it​
evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒F\alpha\frac{q1*q2}{r^{2}}

∴F=k\frac{q1*q2}{r^{2}}

where F is the force of attraction or repulsion

k is Coulumb's constant=9*10^{9}Nm^{2}C^{-2}

q1 and q2 are the magnitude of the charges

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The force between the two charges is attractive if they are of different polarity

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Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

F=9*10^{9}*\frac{0.041*0.029}{12^{2}}

F=74312.5N

Question6:

Given: q1=3*10^{-18}C, r=5 m, F=4*10^{-11}N

therefore by Coulumb's law,

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Answer:

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