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Dmitry [639]
2 years ago
9

HII!!! I need serious help with this assignment so I'm offering half my points so pLS accurately answer!! SO for this assignment

i need to know the order it goes in conducter, battery, or light bulb, battery conducter, light bulb, (ETC...etc....)
Please tell me which order they go in! Also please tell me why it is correct ??

Physics
1 answer:
ehidna [41]2 years ago
3 0

Answer:

Hey, I'm not sure I understand exactly what your assignment is but hopefully this helps . . .

put the other end against the side of the bubls base to light up the light bulb.

This will act as the bulbs conductor, lighting up bc you are making a complete electrical circuit between positive and negative terminals of the battery.

Ok hopefully this helps you out

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According to the law of conservation of energy, which statement must be true?
Nitella [24]

Answer:

B. A system cannot take in additional matter.

Explanation: The total amount of energy in the universe remains constant, it can merely change from one form to another.

Hope it helps you:)))

have a good day

5 0
2 years ago
The light from Barnard's Star takes about 5.94 years to reach Earth. Which of these statements is correct about Barnard's star?
s344n2d4d5 [400]

Answer:

It is located at a distance of 5.94 light years from Earth.

Explanation:

Since light transmitted from the star takes approximately 5.94 years to reach the earth, it means the star is  located at a distance of 5.94 light years from Earth.

7 0
3 years ago
A basebal (radius = .036 m, mas = .145kg) is droped from rest at the top of the Empire State Building (height = 1250ft). Calcula
lora16 [44]

Answer:

a) the initial potential energy = 541.95J

b) the final kinetic energy = 87.991 J

Explanation:

<u>Step 1</u>: Data given

The ball has a mass of 0.145 kg and is at a height of 381m

<u>Step 2</u>: Calculate potential energy

The potential energy = m * g * h

with m = the mass of the ball = 0.145 kg

with g = Gravitational acceleration = 9.81 m/s²

with h = the height of the building = 381m

The potential energy = 0.145 Kg * 9.81 m/s² * 381m = 541.95 J

FD = 1/2ρCDAv²

⇒ with FD = the drag force = the force component in the direction of the flow velocity

⇒ with ρ = density of the fluid (air in our case: ρ≈1.1839 Kg/m3 at 1 atm and 25 °C)

⇒ with v = velocity of the ball

⇒ with A = reference area, which in our case is just the cross sectional area of the ball: A=πr2

⇒ with CD is the drag coefficient - a dimensionless coefficient, that in the case of a sphere, CD=0.47

Following Newton's second law:

ΣFy = may = -mg +Dv²

Here is D=1/2ρCDA ( for convenience) = 0.001172

The terminal speed we can define as the speed of the ball where ay = 0

Therefore: -mg + Dvt² = 0

⇒vt = √(mg/D)

vt = √(0.145 * 9.8 / 0.001172) ≈ 34.837

Uinitial=mgh≈541.951 J (see first question)

Kfinal=1/2*mvt²=(m²g)/2D ≈ 87.991 J

The final kinetics energy is 87.991 J

4 0
4 years ago
What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is 5.66 0.09 m?
iren2701 [21]

Answer:

  • 4.77 %

Explanation:

We know that the volume V for a sphere of radius r is

V(r) = \frac{4}{3} \ \pi \ r^3

If we got an uncertainty \Delta r the formula for the uncertainty of V is:

\Delta V(r) = \sqrt{  (\frac{dV}{dr} \Delta r)^2  }

We can calculate this uncertainty, first we obtain the derivative:

\frac{dV}{dr}  = 3 * \frac{4}{3} \ \pi \ r^2

\frac{dV}{dr}  = 4 \ \pi \ r^2

And using it in the formula:

\Delta V(r) = \sqrt{  (4 \ \pi \ r^2\Delta r)^2  }

\Delta V(r) = \sqrt{  4^2 \ \pi^2 \ r^4 \Delta r^2  }

\Delta V(r) =  4 \  \pi \ r^2 \Delta r

The relative uncertainty is:

\frac{\Delta V(r)}{V(r)}

\frac{ 4 \  \pi \ r^2 \Delta r  }{ \frac{4}{3} \ \pi \ r^3}

\frac{ 3  \Delta r  }{  r}

Using the values for the problem:

\frac{ 3 * 0.09 m  }{  5.66 m} = 0.0477

This is, a percent uncertainty of 4.77 %

4 0
3 years ago
What is the definition for relative motion
xeze [42]
Relative motion is the calculation of the motion of an object with regard to some other moving object.
7 0
3 years ago
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