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inysia [295]
1 year ago
11

suppose the state machine shown below is in state c and receives the string 100010. what is its ending state?

Physics
1 answer:
Sholpan [36]1 year ago
5 0

B is its ending state for the state machine shown below is in state c and receives the string 100010.

<h3>A state machine is difficult to explain.</h3>

A state machine reads a set of inputs and switches states in response to those inputs. A system is said to be in a state when it is waiting to make a transition. A transition is a sequence of steps to carry out when a condition is met or an event is received.

State machines are a type of programming architecture that enable dynamic flow between states based on values from earlier states or user inputs. Applications that can be categorized as a combination of the following fit well with this architecture: States. When to relocate to a specific state, using decision-making logic.

To know more about state machine visit:

brainly.com/question/22967402

#SPJ4

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At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
Citrus2011 [14]

Answer:

a

The height is   H  = 6.74 \  m

b

The horizontal distance is  D  = 23.74 \  m

Explanation:

From the question we are told that

  The speed is  v  =  15 \  m/s

  The angle is  \theta  =  40^o

   The height of the cannon from the ground is  h  =  2 m

  The distance of the net from the ground is k  =  1 m

 

Generally the maximum height she reaches is mathematically represented as  

     H  =  \frac{v^2 sin^2 \theta }{2 *  g }  +  h

=>    H  =  \frac{(15)^2 [sin (40)]^2 }{2 * 9.8}  +  2

=>    H  = 6.74 \  m

Generally from kinematic equation  

    s = ut + \frac{1}{2} at^2

Here s is the displacement which is mathematically represented as

         s  =  [-(h-k)]  

    =>  s =  -(2-1)

    =>  s  = -1 m

There reason why s =  -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half

     a =  -g = -9.8

    u  =  v sin (\theta)

So

    -1 = (vsin 40 )t + \frac{1}{2} * (-9.8) t^2

=>  -4.9t^2 + 9.6418t + 1 = 0

using  quadratic formula to solve the equation we have

    t  =  2.07 \  s

Generally distance covered along the horizontal is  

   D  =  v cos (40) *  2.07

=>   D  =  15 cos (40) *  2.07

=>   D  = 23.74 \  m

7 0
3 years ago
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Radiation. That's perhaps the only way that energy gets from the Sun to the earth. The space between the two is a vacuum, so conduction is more or less out as is convection. There's no obvious sign of mirrors, so reflection seems to be out as well.
8 0
3 years ago
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An industrial overhead door has a chain and sprocket system designed to reduce the force needed by an operator to open and close
mylen [45]
GR/1=nout/nin = 48/22=2.18/1
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matrenka [14]

Answer:

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Explanation:

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