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nika2105 [10]
3 years ago
6

Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs t

o run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?
Physics
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

Speed greater than 4 m/s

Explanation:

Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?

The distance = 12 m

Time = 3s

Speed = distance/time

Speed = 12/3

Speed = 4 m/s

Ms Kasper must run at speed more than 4m/s for her to save the cat.

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1) The average velocity is 56 m/min

2) The average velocity is -83 m/min

Explanation:

1)

The average velocity of an object is given by

v=\frac{d}{t}

where

d is the displacement (change in position)

t is the time elapsed

In the graph in the problem, the displacement corresponds to the distance, therefore to the change in the y-variable (\Delta y), while the time elapsed is the change in the x-variable (\Delta x), so the average velocity can be written as

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At point A, we have:

y_A = 5 m\\x_A = 0.1 min

At point B, we have:

y_E = 55 m\\x_A = 1 min

So, we have

\Delta y= 55 -5 = 50 m\\\Delta x = 1.0-0.1 = 0.9 min

So the average velocity is

v=\frac{50 m}{0.9 min}=56 m/min

2)

In this part instead, we have the following:

At point F, we have:

y_F = 55 m\\x_A = 1.3 min

At point H, we have:

y_H = 30 m\\x_A = 1.6 min

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\Delta y= 30 -55 = -25 m\\\Delta x = 1.6-1.3 = 0.3 min

So the average velocity is

v=\frac{-25 m}{0.3 min}=-83 m/min

Learn more about velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

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